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2 years ago

What is 225/23*488-236b=4428

2 answers:

7 0

$\sf \frac{225}{23} (488)-236b = 4428 \\ \\ \frac{109800}{23} + - 236b = 4428 \\ \\ -236b + \frac{109800}{23} = 4428 \\ \\ -236+ \frac{109800}{23} - \frac{109800}{23} = 4428 - \frac{109800}{23} \\ \\ -236b = \frac{-7956}{23} \\ \\ \boxed{{{\huge{{\bold{b = \dfrac{1989}{1357} }}}}}}$

vesna_86 [32]2 years ago

5 0

Solution

1 Simplify $\frac{225}{23}$ ×488 to $\frac{109800}{23}$ 
 $\frac{109800}{23}$ −236b=4428

Subtract $\frac{109800}{23}$ from both sides
−236b=4428− $\frac{109800}{23}$

Simplify 4428− $\frac{109800}{23}$ to − $\frac{7956}{23}$
−236b=− $\frac{7956}{23}$

Divide both sides by −236
b= - $\frac{7956}{23}$ / 236

Simplify $\frac{7956}{23}$ / 236

Simplify $\frac{7956}{23}$ to b= $\frac{7956}{23}$ ×236

Simplify to $\frac{7956}{5428}$

Simplify $\frac{7956}{5428}$ to $\frac{1989}{1357}$

B = $\frac{1989}{1357}$

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"Immediately after a ban on using hand-held cell phones while driving was implemented, compliance with the law was measured. A r

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Alternate Hypothesis, $H_A$ : $p_1-p_2\neq 0$ or $p_1\neq p_2$

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Step-by-step explanation:

We are given that a random sample of 1,250 drivers found that 98.9% were in compliance. A year after the implementation, compliance was again measured to see if compliance was the same (or not) as previously measured.

A different random sample of 1,100 drivers found 96.9% compliance."

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$p_2$ = proportion of drivers that were in compliance one year later

(a) Null Hypothesis, $H_0$ : $p_1-p_2=0$ or $p_1= p_2$ {means that there is not any statistical difference in these two proportions measured initially and then one year later}

Alternate Hypothesis, $H_A$ : $p_1-p_2\neq 0$ or $p_1\neq p_2$ {means that there is a statistical difference in these two proportions measured initially and then one year later}

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$n_2$ = sample of drivers one year later = 1,100

(b) So, the test statistics = $\frac{(0.989-0.969)-(0)}{\sqrt{ \frac{0.989(1-0.989)}{1,250} + \frac{0.969(1-0.969)}{1,100}} }$

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