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Lemur [1.5K]
3 years ago
5

ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
ivann1987 [24]3 years ago
7 0

It would be similar.

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Starting at home, Luis traveled uphill to the gift store for 50 minutes at just 6 mph. He then traveled back home along the same
mario62 [17]

Average speed for the entire trip, both ways, is

                 (Total distance) divided by (total time) .

We don't know the distance from his house to the gift store,
and we don't know how long it took him to get back.
We'll need to calculate these.

-- On the trip TO the store, it took him 50 minutes, at 6 mph.
-- 50 minutes is 5/6 of an hour.
-- Traveling at 6 mph for 5/6 of an hour, he covered 5 miles.
-- The gift store is 5 miles from his house.
-- The total trip both ways was 10 miles.

-- On the way BACK home from the store, he moved at 12 mph.
-- Going 5 miles at 12 mph, it takes  (5/12 hour) = 25 minutes.

Now we have everything we need.

Distance:
         Going:       5 miles
         Returning:  5 miles
         Total         10 miles

Time:
         Going:        50 minutes
         Returning:   25 minutes
         Total:          75 minutes  =  1.25 hours  

         Average speed for the whole trip =

                       (total distance) / (total time)

                   =      (10 miles)  /  (1.25 hours)

                   =       (10 / 1.25)  miles/hours 

                   =          8 miles per hour
4 0
3 years ago
Two functions, P and Q, are described as follows: Function P y = 5x + 3 Function Q The rate of change is 2 and the y-intercept i
Svetach [21]

Function P . . . . . y = 5x + 3

Function Q . . . . . y = 2x + 4

Function P rate of change  =  5
Function Q rate of change  =  2

The first one is  => 3 <=  more than second one.
7 0
3 years ago
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Please help me! Thanks.
Vedmedyk [2.9K]

Answer:

129 is yr ANSWER........

5 0
3 years ago
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