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2 years ago

6

Ronald states that The number 1/11 is not rational because when converted into a decimal it is not terminate Nathaniel says it’s

a rational because it’s a fraction which voice correct

1 answer:

gregori [183]2 years ago

5 0

Nathaniel is correct. fractions are rational numbers

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You have six pizza toppings. How many different 3-topping pizzas can you make?

velikii [3]

Answer is to the question is 20

5 0

2 years ago

Write each of the following products in standard polynomial form. (a) (x+3)(x-2)(x-8) (b) (x+2)(x-2)(x+3)(x-3)

Grace [21]

Each of the following products

6 0

2 years ago

M is proportional to the cube of r. when r=3m,m=216.when r=5 find the value of m

klio [65]

Answer:

The value of m is 1000 for r=5

Step-by-step explanation:

Given that m is proportional to the cube of r

It can be written as:

$m \propto\ r^3$

When the proportionality symbol is removed a proportionality constant is introduced in the equation.

Let k be the proportionality constant

$m = kr^3$

Given

r=3,m=216

Putting the values

$216 = k(3)^3\\216 = k * 27\\k = \frac{216}{27}\\k = 8$

The equation will now become

$m = 8r^3$

Putting r = 5

$m = 8(5)^3\\m = 8 * 125\\m = 1000$

Hence,

The value of m is 1000 for r=5

7 0

2 years ago

Can someone help I cant understand a method for this pls ASAP

kvv77 [185]

Answer:

105 hours

Step-by-step explanation:

→ Find how many days in a week

7

→ Multiply this by his gaming time

7 × 15 = 105

3 0

1 year ago

Read 2 more answers

Circle O, with center (x, y) passes through the points A(0, 0), B(-3, 0), and C(1, 2). Find the coordinates of the center of the

KonstantinChe [14]

Answer:

The center of the circle is

$(-\frac{3}{2},2)$

Step-by-step explanation:

Let the equation of the circle be

$x^2+y^2+2ax+2by+c=0$ , where (-a,-b) is the center of this circle.

The points lying the circle must satisfy the equation of this circle.

A(0,0)

We substitute this point to get;

$0^2+0^2+2a(0)+2b(0)+c=0$

$\implies c=0$

B(-3,0)

$(-3)^2+0^2+2a(-3)+2b(0)+c=0$

$\implies 9+0-6a+0+c=0$

$\implies -6a+c=-9$

But c=0

$\implies -6a=-9$

$\implies a=\frac{3}{2}$

C(1,2)

$1^2+2^2+2a(1)+2b(2)+c=0$

$1+4+2a+4b+c=0$

$2a+4b+c=-5$

Put the value of 'a' and 'c' to find 'b'

$2(\frac{3}{2})+4b+0=-5$

$3+4b+0=-5$

$4b=-5-3$

$4b=-8$

b=-2

Hence the center of the circle is

$(-\frac{3}{2},2)$

8 0

2 years ago