Answer:
The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 24 - 1 = 23
98% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 23 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 2.5
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 42 - 1.02 = $40.98.
The upper end of the interval is the sample mean added to M. So it is 42 + 1.02 = $43.02.
The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.
36 becomes a negative
First -36 + -1 -37
Next: -18 + -2 = -20
Next: -12 + -3 = -15
Next: -9 + -4 which equals -13
Finally we get to the last part: -6 + -6 = -12
We change z2 to
- 6(z) = 36
z(z) - 6
Because, we add up for the first two terms
Switch up, up the problem 6(z) - 6
Now, let's add the number 4 on the terms
z - 6 (z - 6)
Then, let's multiply z - 6 from z - 6
From this problem we have to add 6 from the sides that we are working with
Therefore, your answer for z is 6
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Answer:
C. 92 degrees
Step-by-step explanation:
Given that the 
92° which is one of the angles of the quadrilateral WXYZ
The quadrilateral is first rotated by 270° about the origin and then translated 2 units up, the new position of the quadrilateral is W'X'Y'Z'.
The shape of the quadrilateral is remained unchanged due to rotation and translation, so all the angles of the final quadrilateral W'X'Y'Z' is the same as the angles of the given quadrilateral WXYZ.
So,
By using the given value,
92°
Hence, option (C) is correct.
