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2 years ago

Solve for x.2(-x - 4) = 4x + 16 a) 4 b) 3 c) -3 d) -4

Mathematics

2 answers:

gladu [14]2 years ago

3 0

Answer:

Step-by-step explanation:

seraphim [82]2 years ago

3 0

Answer:

Step-by-step explanation:

First, we must solve for the parenthesis so...

-2x-8=4x+16

Then we must simplify this even more so lets add the 8 to 16

-2x=4x+24

Then we must subtract 4x from -2x

-6x=24

we must now divide 24 by -6 so we can isolate the x

x=-4

I hope this helped :)

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Let vector u = (a, b) and vector v = (c, d). If the vectors are located as shown in the graph, then

AlekseyPX

We have the following vectors:
u = (a, b)
v = (c, d)
We observe that the vectors form an angle of 90 degrees.
Therefore, the product u.v is equal to zero.
We have then:
u.v = (a, b). (c, d) = 0
u.v = ac + bd = 0
ac = -bd
Answer:
B) ac = -bd

6 0

2 years ago

Evaluate the discriminant for the equation. Then use it to predict the number of distinct solutions, and whether they are ration

sweet-ann [11.9K]

T=-4

Hope this help…

3 0

1 year ago

-5 + a =21 what’s A?

KonstantinChe [14]

Answer:

A=21+5

A=26

Step-by-step explanation:

just shift 5 to right side

3 0

3 years ago

The radius of the base of a cylinder is increasing at a rate of 11 meter per hour and the height of the cylinder is decreasing a

musickatia [10]

Answer:

The volume of the cylinder is decreasing at a rate of 83629.2 m³/h.

Step-by-step explanation:

The volume of a is given by:

$V = \pi r^{2}h$

Where:

r: is the radius = 55 m

h: is the height = 88 m

We can express the rate of change of the volume of the cylinder as follows:

$\frac{dV}{dt} = \pi[h\frac{2rdr}{dt} + r^{2}\frac{dh}{dt}]$

If dr/dt = 11 m/h and dh/dt = -44m/h, we have:

$\frac{dV}{dt} = \pi[88 m*2*55 m*11 m/h + (55 m)^{2}*(-44 m/h)] = -83629.2 m^{3}/h$

Therefore, the volume of the cylinder is decreasing at a rate of 83629.2 m³/h.

I hope it helps you!

5 0

2 years ago

What is the discriminant of the quadratic equation 2x² - x - 3=0?

Tamiku [17]

The given quadratic equation is

$2 {x}^{2} - x - 3 = 0$

comparing with

${ax}^{2} + bx + c = 0$

We get ,

$a = 2 \\ b = - 1 \\ c = - 3$

formula :

$D = {b}^{2} - 4ac \\ \\ D = {( - 1)}^{2} - 4 \times 2 \times ( - 3) \\ \\ D = 1 - ( - 24) \\ \\D = 1 + 24 \\ \\D = 25.$

Discriminant of given quadratic equation is 25 .

option (B) 25 ✔

6 0

1 year ago