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Vladimir [108]
3 years ago
12

You are a researcher with an interest in understanding the mechanism of serine protease enzymes. To test the effect of the role

of Asp102 in the efficiency of catalysis, you make targeted substitutions of that residue and compare the rate of hydrolysis of p-nitrophenyl acetate with the rate on the unmutated enzyme. Answer the following questions: a. (4) You observe a bi-phasic plot, i.e. a quick burst of product (p-nitrophenol) release (seen as a steep curve), followed by a slower (less steep) curve. What step of the reaction corresponds to each phase of the chymotrypsin reaction? And which corresponds to the Michaelis-Menten Steady State? Explain. b. (4) If you mutate Asp102 to create an enzyme with Asn102, describe (or draw) changes you would expect to see in p-nitrophenol release – and, of course, explain your answer. c. (4-8) For the wild type (unmutated) enzyme, you measure a rate of p-nitrophenol release by the change in absorbance at 405 nm (for the slower phase only) of 0.216 (in a cuvette with a pathlength of 1 cm) over the course of two minutes. Use the Beer-Lambert Law to calculate the concentration of product released over this time; the extinction coefficient of p-nitrophenol at 405 nm is 18,000 M-1 cm-1. For extra credit: If your assay is done with 1 x 10-9 M enzyme, what is the turnover number for this enzyme?
Chemistry
1 answer:
yawa3891 [41]3 years ago
5 0
Ngl didn’t read it so I’m not gonna answer it. Don’t report please just want to ask a question but have to answer two
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Why did Rutherford choose alpha particles in his experiment?
Georgia [21]
Rutherford used gold for his scattering experiment because gold is the most malleable metal and he wanted the thinnest layer as possible. The goldsheet used was around 1000 atoms thick. Therefore, Rutherford selected a Gold foil in his alpha scatttering experiment.
5 0
3 years ago
Perform the calculation and record the answer with the correct number of significant figures.
kotykmax [81]

The question is incomplete, here is the complete question:

A. (6.5-6.10)/3.19

B. (34.123 + 9.60) / (98.7654 - 9.249)

<u>Answer:</u>

<u>For A:</u> The answer becomes 0.1

<u>For B:</u> The answer becomes 0.4884

<u>Explanation:</u>

Significant figures are defined as the figures present in a number that expresses the magnitude of a quantity to a specific degree of accuracy.

Rules for the identification of significant figures:

  • Digits from 1 to 9 are always significant and have infinite number of significant figures.
  • All non-zero numbers are always significant. For example: 664, 6.64 and 66.4 all have three significant figures.
  • All zeros between the integers are always significant. For example: 5018, 5.018 and 50.18 all have four significant figures.
  • All zeros preceding the first integers are never significant. For example: 0.00058 has two significant figures.
  • All zeros after the decimal point are always significant. For example: 2.500, 25.00 and 250.0 all have four significant figures.
  • All zeroes used solely for spacing the decimal point are not significant. For example: 10000 has one significant figure.

<u>Rule applied for addition and subtraction:</u>

The least precise number present after the decimal point determines the number of significant figures in the answer.

<u>Rule applied for multiplication and division:</u>

In case of multiplication and division, the number of significant digits is taken from the value which has least precise significant digits

  • <u>For A:</u> (6.5-6.10)/3.19

This a a problem of subtraction and division.

First, the subtraction is carried out.

\Rightarow \frac{6.5-6.10}{3.19}=\frac{0.4}{3.19}

Here, the least precise number after decimal was 1.

\Rightarrow \frac{0.4}{3.19}=0.125

Here, the least precise number of significant digit is 1. So, the answer becomes 0.1

  • <u>For B:</u> (34.123 + 9.60) / (98.7654 - 9.249)

This a a problem of subtraction, addition and division.

First, the subtraction and addition is carried out.

\Rightarow \frac{34.123+9.60}{98.7654-9.249}=\frac{43.723}{89.5164}=\frac{43.72}{89.516}

Here, the least precise number after decimal in addition are 2 and in subtraction are 3

\Rightarrow \frac{43.72}{89.516}=0.48840

Here, the least precise number of significant digit are 4. So, the answer becomes 0.4884

6 0
3 years ago
How many molecules are there in 2.30g of NH3
Vinil7 [7]

Answer:

8.13x10^22 molecules

Explanation:

We can use the Avogadro's number(6.022 x 10^23 units / mole)

2.30 g NH3 (1 mol / 17.03 g ) (6.022 x 10^23 molecules / 1 mol ) = 8.13x10^22 molecules

Hope this helps! Feel free to ask any questions!

6 0
3 years ago
Which molecule is amphoteric?<br><br> A) NH4+<br><br> B )H2O<br><br> C )H2CO3−<br><br> D )H2SO4
Maslowich
The answer is letter choice B



4 0
4 years ago
Read 2 more answers
At one point in your life, you might have played on a swing. Have you ever wondered why, after the first swing, it will slow dow
cestrela7 [59]

Answer:

at the top of the swing

at the top of the swing

at the bottom of the swing

at the bottom of the swing

Explanation:

7 0
3 years ago
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