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Vladimir [108]
3 years ago
12

You are a researcher with an interest in understanding the mechanism of serine protease enzymes. To test the effect of the role

of Asp102 in the efficiency of catalysis, you make targeted substitutions of that residue and compare the rate of hydrolysis of p-nitrophenyl acetate with the rate on the unmutated enzyme. Answer the following questions: a. (4) You observe a bi-phasic plot, i.e. a quick burst of product (p-nitrophenol) release (seen as a steep curve), followed by a slower (less steep) curve. What step of the reaction corresponds to each phase of the chymotrypsin reaction? And which corresponds to the Michaelis-Menten Steady State? Explain. b. (4) If you mutate Asp102 to create an enzyme with Asn102, describe (or draw) changes you would expect to see in p-nitrophenol release – and, of course, explain your answer. c. (4-8) For the wild type (unmutated) enzyme, you measure a rate of p-nitrophenol release by the change in absorbance at 405 nm (for the slower phase only) of 0.216 (in a cuvette with a pathlength of 1 cm) over the course of two minutes. Use the Beer-Lambert Law to calculate the concentration of product released over this time; the extinction coefficient of p-nitrophenol at 405 nm is 18,000 M-1 cm-1. For extra credit: If your assay is done with 1 x 10-9 M enzyme, what is the turnover number for this enzyme?
Chemistry
1 answer:
yawa3891 [41]3 years ago
5 0
Ngl didn’t read it so I’m not gonna answer it. Don’t report please just want to ask a question but have to answer two
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Calculate the empirical formula the compound with the following percent composition: 27.59%C 1.15%H 16.09%N 55.17%O
jeyben [28]

Answer: C2HNO3

Explanation: C = 27.59/12.011 = 2.297

H = 1.15/1.008 = 1.1409

N = 16.09/14.007 = 1.1487

O = 55.17/15.999 = 3.4483

Divide by smallest result:

C = 2

H=1

N=1

O = 3

Empirical formula = C2HNO3

8 0
3 years ago
Briefly explain formality in solution.
Zielflug [23.3K]

Answer:

Both molarity and formality express concentration as moles of solute per liter of solution. Formality is a substance's total concentration in solution without regard to its specific chemical form. ... The formality of a solution is defined as the number of formula mass of any solute dissolved in 1 litre of solution.

4 0
3 years ago
You are given a sulfuric acid solution of unknown concentration. You dispense 10.00 mL of the unknown solution into an Erlenmeye
dmitriy555 [2]

Answer:

"0.053457 M" of sulfuric acid.

Explanation:

The given values are:

V = 10 mL solution

V_{added} = 12.20 mL

V_{total} = 22.20 mL

then,

M 0.103 M of NaOH,

V_{rinsed} = experiment  will not be affected

V_{total \ base} = 10.38 mL

Now,

⇒  mol of NAOH = MV

                            = 0.103\times 10.38

                            =  1.06914  \ m

Whether Sulfuric acid, then

⇒  H_{2}SO_{4} + 2NaOH = Na_{2}SO_{4} + 2H_{2}O

⇒  mol \ of \ acid =\frac{1}{2}\times \ mol \   of  \ base

⇒  1.06914 \ m \ mol \ of \ base = \frac{1}{2}\times 1.06914 = 0.53457 \ m \ mol \ of \ acid

Before any dilution:

V_{sample} = 10  \ mL

⇒  M \ acid = \frac{m \ mol}{V}

                 =\frac{ 0.53457 }{10}

                 =0.053457 \ M (Sulfuric acid)

6 0
3 years ago
As an athlete exercises, sweat is produced and evaporated to help maintain a proper body temperature. On average, an athlete los
dmitriy555 [2]

<u>Answer:</u> For the given amount of sweat lost, the amount of energy required will be 692,899 Joules.

<u>Explanation:</u>

We are given:

Heat of vaporization for water = 2257 J/g

Amount of sweat lost = 307 grams

Applying unitary method:

For 1 g of sweat lost, the energy required is 2257 Joules

So, for 307 grams of sweat lost, the energy required will be = \frac{2257J}{1g}\times 307g=692,899J

Hence, for the given amount of sweat lost, the amount of energy required will be 692,899 Joules.

7 0
2 years ago
Flowers usually contain more stamen than pistils. Why do you think this is ?
Gemiola [76]
What kind of question is this 

8 0
3 years ago
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