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andriy [413]
3 years ago
8

Please can any one help me by answering this question!!+ignore my answer!,

Chemistry
1 answer:
den301095 [7]3 years ago
8 0

I have posted the answetr in this picture.

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Goshia [24]

Answer:

The correct answer is D) hydration

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The boiling point elevation of an aqueous sucrose solution is found to be 0.39°C.
SVEN [57.7K]

Answer:

130.4 grams of sucrose, would be needed to dissolve in 500 g of water.

Explanation:

Colligative property of boiling point elevation:

ΔT = Kb . m . i

In this case, i = 1 (sucrose is non electrolytic)

ΔT = Kb . m

0.39°C = 0.512°C/m . m

0.39°C /0.512 m/°C = m

0.762 m (molality means that this moles, are in 1kg of solvent)

If in 1kg of solvent, we have 0.712 moles of sucrose, in 500 g, which is the half, we should have, the hallf of moles, 0.381 moles

Molar mass sucrose = 342.30 g/m

Molar mass . moles = mass

342.30 g/m . 0.381 m = 130.4 g

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Not including the noble gases, which area of the periodic table has the highest electronegativities?
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At a certain temperature, the solubility of strontium arsenate, sr3(aso4)2, is 0.0550 g/l. what is the ksp of this salt at this
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