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andriy [413]
3 years ago
8

Please can any one help me by answering this question!!+ignore my answer!,

Chemistry
1 answer:
den301095 [7]3 years ago
8 0

I have posted the answetr in this picture.

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Determine the pH of a 5x10^-4 M solution of Ca(OH)2
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Ca(OH)₂ ==> Ca²⁺ + 2 OH<span>-   

Ca(OH)</span>₂ is <span>strong Bases</span><span>

</span>Therefore,  the [OH-] equals 5 x 10⁻⁴ M. For every Ca(OH)₂ you produce 2 OH⁻<span>.
</span>
pOH = - log[ OH⁻]

pOH = - log [ <span>5 x 10⁻⁴ ]

pOH = 3.30

pH + pOH = 14

pH + 3.30 = 14

pH = 14 - 3.30

pH = 10.7

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If you set up an experiment with two different independent variables, then the results would be_____.
MariettaO [177]

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