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Andre45 [30]
3 years ago
6

HELP ME PLEASE!!!!

Chemistry
2 answers:
liq [111]3 years ago
6 0

Answer:

1.D

2.A

3.C

4.A

Explanation:

alexira [117]3 years ago
6 0

Answer:

its A

Explanation:

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A chemist must dilute of aqueous aluminum chloride solution until the concentration falls to . He'll do this by adding distilled
marshall27 [118]

Answer:

0.257 L

Explanation:

The values missing in the question has been assumed with common sense so  that the concept could be applied

Initial volume of the AICI3 solution =23.1 \mathrm{mL}

Initial Molarity of the solution =833 \mathrm{mM}

Final molarity of the solution =75.0 \mathrm{mM}

Final volume of the solution =?

From Law of Dilution, M_{f} V_{f}=M_{i} V_{i}

\Rightarrow V_{f}=\frac{M_{i} V_{i}}{M_{f}}=\frac{833 \mathrm{mM} \times 23.1 \mathrm{mL}}{75.0 \mathrm{mM}}=256.564 \mathrm{mL}=0.256564 \mathrm{L}=0.257 L

Final Volume of the solution =0.257

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3 years ago
Aluminum reacts with sulfur gas to produce aluminum sulfide
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Answer:

What is the question? It looks like a fact.

Explanation:

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3 years ago
Which statement is true if the Hrxn of a reaction is positive?
erma4kov [3.2K]
I think it is b..................................................
7 0
3 years ago
Read 2 more answers
5. What concentration of acid must be added to change the pH of 1 mM phosphate buffer from 7.4 to 7.3 (pKas of the phosphate buf
mr_godi [17]

Explanation:

According to the Henderson-Hasselbalch equation, the relation between pH and pK_{a} is as follows.

               pH = pK_{a} + log \frac{base}{acid}

where,     pH = 7.4 and pK_{a} = 7.21

As here, we can use the pK_{a} nearest to the desired pH.

So,      7.4 = 7.21 + log \frac{base}{acid}

             0.19 = log \frac{base}{acid}

            \frac{base}{acid} = 1.55

1 mM phosphate buffer means [HPO_{4}] + [H_{2}PO_{4}] = 1 mM

Therefore, the two equations will be as follows.

           \frac{HPO_{4}}{H_{2}PO_{4}} = 1.55 ............. (1)

  [HPO_{4}] + [H_{2}PO_{4}] = 1 mM ........... (2)        

Now, putting the value of [HPO_{4}] from equation (1) into equation (2) as follows.

             1.55[H_{2}PO_{4}] + [tex][H_{2}PO_{4}] = 1 mM

                        2.55 [H_{2}PO_{4}] = 1 mM

                             [H_{2}PO_{4}] = 0.392 mM

Putting the value of [H_{2}PO_{4}] in equation (1) we get the following.

                     0.392 mM + [HPO_{4}] = 1 mM

                          [HPO_{4}] = (1 - 0.392) mM

                              [HPO_{4}] = 0.608 mM

Thus, we can conclude that concentration of the acid must be 0.608 mM.

7 0
3 years ago
Suppose you place a ball in the middle of a wagon, and then accelerate the wagon forward. Describe the motion of the ball relati
Alborosie

Answer:

It will have more speed/more acceleration than or the ground.

Explanation:

It will lean twords the side that moves and for ex if the wagon has a level to pull a gap down the ball will go forward

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3 years ago
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