Answer:
<h3>80 feet</h3>
Step-by-step explanation:
Given the path of a projectile launched from a 16-ft-tall tower modeled by the equation y = −16t^2 + 64t +16
h is the maximum height reached
t is in seconds
The velocity of the projectile at its maximum height is zero;
velocity v = dy/dt
v = -32t + 64
Since v = 0 at maximum height
0 = -32t + 64
32t = 64
t = 2secs
Substitute t = 2secs into the equation of the height to get the maximum height.
y = −16t^2 + 64t +16
at t = 2secs
y = −16(2)^2 + 64(2) +16
y = -64 + 128 + 16
y = 64+16
y = 80 feet
Hence the maximum height, in feet, reached by the projectile is 80 feet
9514 1404 393
Answer:
12 ft
Step-by-step explanation:
Let the width of the room be represented by w. Then the length is (2w-2), and the area is ...
A = LW
264 = (2w-2)w
132 = w² -w . . . . . . . divide by 2, eliminate parentheses
132.25 = w² -w +.25 . . . . . add (-1/2)² to complete the square
√132.25 = w -0.5 . . . . . take the square root
0.5 +11.5 = w = 12 . . . . . add 0.5; use the positive root
The width of the living room is 12 feet.
Answer:
29
Step-by-step explanation:
if you do 58 divided by 2 you get 29 so Mr. John doubles 29.
Hey!
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Solve for A:
A = 3.6 * (3/4 + 2/9 + 5/12)
A = 3.6 * (27/36 + 8/36 + 15/36)
A = 3.6 * (50/36)
A = 18/5 * 50/36
A = 900/180
A = 5
Answer:
A = 5
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Solve for B:
B = (84.8 * 0.125) ÷ (10.07 ÷ 0.95)
B = 10.6 ÷ 10.6
B = 1
Answer:
B = 1
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Solve for C:


Answer:
C = 15
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Solve for D:
D = 0.28 * 4,500 ÷ 35 * 1/12
D = 1,260 ÷ 35 * 1/12
D = 36 * 1/12
D = 3
Answer:
D = 3
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Data Set:
1, 3, 5, 15
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Final Answer:
A proportion cannot be made by these numbers.
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Hope This Helped! Good Luck!