Answer:
line1:y=2x+3
Gradient1=2
Let line2 be the line passes through (-4,1)and perpendicular to line1.
Because line2 and line1 are perpendicular, (gradient of line2) (gradient of line1) =-1
Gradient of line2=-1/2
Equation of line2:y-y1 =m(x-x1)
:y-1 =(-1/2)[x-(-4)]
:(y-1)(-2)=(x+4)
:-2y+2 =x+4
:-2y+2-x-4=0
:-x-2y-2 =0
:x+2y+2 =0
*notes:gradient=m
By a Challenge that way It’ll be even
