Answer:
6.7% of employees at Solar Systems, Inc. are younger than 30 years old
Step-by-step explanation:
The mean of ages of the employees at Solar Systems is 32.7 years
Mean =
Standard deviation =
We are supposed to find What percentage of employees at Solar Systems, Inc. are younger than 30 years old i.e.P(x<30)
So,
Z=-1.5
Refer the z table for p value
So,p value = 0.0668
So P(x<30)=0.0668= 6.68% = 6.7%
So, 6.7% of employees at Solar Systems, Inc. are younger than 30 years old
Answer:
(a) 0.119
(b) 0.1699
Solution:
As per the question:
Mean of the emission, million ponds/day
Standard deviation, million ponds/day
Now,
(a) The probability for the water pollution to be at least 15 million pounds/day:
= 1 - P(Z < 1.178)
Using the Z score table:
= 1 - 0.881 = 0.119
The required probability is 0.119
(b) The probability when the water pollution is in between 6.2 and 9.3 million pounds/day:
P(Z < - 0.86) - P(Z < - 1.96)
Now, using teh Z score table:
0.1949 - 0.025 = 0.1699