Answer:
t=11
Step-by-step explanation:
31-20=11
so 11 miles left
Answer:
29.49% probability that a production time is between 9.7 and 12 minutes
Step-by-step explanation:
An uniform probability is a case of probability in which each outcome is equally as likely.
For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.
The probability that we find a value X between c and d, in which d is greater than c, is given by the following formula.

Production times are evenly distributed between 8 and 15.8 minutes and production times are never outside of this interval.
This means that 
What is the probability that a production time is between 9.7 and 12 minutes?
.
So


29.49% probability that a production time is between 9.7 and 12 minutes
<u>Answer:</u>
A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.
<u>Solution:</u>
We need to show that the gradient of the curve at A is 1
Here given that ,
--- equation 1
Also, according to question at point A (b+1,0)
So curve at point A will, put the value of x and y

0=b+1-c --- equation 2
According to multiple rule of Differentiation,

so, we get



By putting value of point A and putting value of eq 2 we get


Hence proved that the gradient of the curve at A is 1.
3857/10000 I can’t simply. But that’s what Siri gave me