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2 years ago

Will mark brainliest (NO LINKS OR ANSWERS WITHOUT EXPLANATION)

Mathematics

2 answers:

Ilia_Sergeevich [38]2 years ago

6 0

Answer: i think the answer is 6x2−xy−35y2

LenKa [72]2 years ago

3 0

Answer:

6x² -xy -35y²

Step-by-step explanation:

Use the distributive property, and combine terms.

(2x +5y)(3x -7y) -2xy

= 2x(3x -7y) +5y(3x -7y) -2xy

= 6x² -14xy +15xy -35y² -2xy

= 6x² +(-14 +15 -2)xy -35y²

= 6x² -xy -35y²

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In the interval 0≤x<360°

dedylja [7]

Answer:

Step-by-step explanation:

since -1≤sin2x≤1 no x values would satisfy the equation

5 0

2 years ago

See attached picture, is there a way to enter equations or algebraic symbols?

coldgirl [10]

SOLUTIONS

Solve a given equations or algebraic symbols?

$\begin{gathered} f(x)=x^2+2x \\ g(x)=1-x^2 \end{gathered}$

(A)

$\begin{gathered} (f+g)(x)=(x^2+2x)+(1-x^2) \\ collect\text{ like terms} \\ x^2-x^2+2x+1 \\ (f+g)(x^)=2x+1 \end{gathered}$

(B)

$\begin{gathered} (f-g)(x)=(x^2+2x)-(1-x^2) \\ =x^2+2x-1+x^2 \\ =x^2+x^2+2x-1 \\ (f-g)(x)=2x^2+2x-1 \end{gathered}$

(C)

$\begin{gathered} fg(x)=(x^2+2x)(1-x^2) \\ =x^2-x^4+2x-2x^3 \\ fg(x)=-x^4-2x^3+x^2+2x \end{gathered}$

(D)

$\begin{gathered} \frac{f}{g}(x)=(x^2+2x)\div(1-x^2) \\ =\frac{x^2+2x}{1-x^2} \end{gathered}$

5 0

1 year ago

(2) (x-7) (=3) (x+8)

Tasya [4]

Use the distributive property to get 2x - 14 = 3x + 24. Subtract 24 from both sides to get 2x - 38 = 3x. Subtract 2x from both sides to get -38 = x.

7 0

3 years ago

Read 2 more answers

Complete the steps to solve the polynomial equation x3 – 21x = –20. According to the rational root theorem, which number is a po

jeka94

Answer:

Zeroes : 1, 4 and -5.

Potential roots: $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .

Step-by-step explanation:

The given equation is

$x^3-21x=-20$

It can be written as

$x^3+0x^2-21x+20=0$

Splitting the middle terms, we get

$x^3-x^2+x^2-x-20x+20=0$

$x^2(x-1)+x(x-1)-20(x-1)=0$

$(x-1)(x^2+x-20)=0$

Splitting the middle terms, we get

$(x-1)(x^2+5x-4x-20)=0$

$(x-1)(x(x+5)-4(x+5))=0$

$(x-1)(x+5)(x-4)=0$

Using zero product property, we get

$x-1=0\Rightarrow x=1$

$x-4=0\Rightarrow x=4$

$x+5=0\Rightarrow x=-5$

Therefore, the zeroes of the equation are 1, 4 and -5.

According to rational root theorem, the potential root of the polynomial are

$x=\dfrac{\text{Factor of constant}}{\text{Factor of leading coefficient}}$

Constant = 20

Factors of constant ±1, ±2, ±4, ±5, ±10, ±20.

Leading coefficient= 1

Factors of leading coefficient ±1.

Therefore, the potential root of the polynomial are $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .

3 0

3 years ago

The difference of five times a number and one is 24 find the number

dimaraw [331]

<h2>Answer:</h2><h2>let number be x</h2><h2>Step-by-step explanation:</h2><h2>5x - 1 = 24</h2><h2>5x = 25</h2><h2>x = 5</h2>

3 0

3 years ago