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Annette [7]
3 years ago
10

Josette found 16 coins in her purse. She had 2 more nickels than pennies and 7 fewer quarters than pennies. Josette modeled the

scenario in a table and then wrote the equation p + (p + 2) + (7 – p) = 16.
Is Josette’s equation correct? If not, what was her mistake.

A): Her equation is correct.

B): The variable should have been the number of nickels.

C): Instead of finding the sum, she needed to write an equation to find the difference.

D): The number of quarters was translated incorrectly and should be p – 7.

Mathematics
2 answers:
Yanka [14]3 years ago
6 0

Answer:

D

Step-by-step explanation:

mario62 [17]3 years ago
4 0

Answer:

D.The number of quarters was translated incorrectly and should be p – 7.

Step-by-step explanation:

I had the same question.

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A student needs to make a circular cardboard piece with an area between 154 square inches and 616 square inches. The function f(
Nezavi [6.7K]
The area of the circle by definition is given by:
 f (r) =  \pi  * r ^ 2

 For f (r) = 154:
 154 =  \pi  * r ^ 2

 Clearing r we have:
 r ^ 2 = 154 / 3.14

 r =  \sqrt{154/3.14} 

 r = 7
 For f (r) = 616:
 616 = \pi * r ^ 2
 Clearing r we have:
 r ^ 2 = 616 / 3.14 r = \sqrt{616/3.14} r = 14
 Answer:
 
a reasonable domain for f (r) is:
 
7 <r <14
3 0
3 years ago
A store had 150 laptops in the month of January. Every month, 20% of the laptops were sold and 10 new laptops were stocked in th
Softa [21]

<u>Answer-</u>

\boxed{\boxed{f(n)=0.8(f(n-1))+10,\ f(0)=150,\ \ n>0}}

<u>Solution-</u>

Here, n represents the number of months and f(n) represents the number of laptops in the store after n months.

As the store had 150 laptops in the month of January or at the beginning.

So f(0)=150

Every month, 20% of the laptops were sold and 10 new laptops were stocked in the store.

As 20% of laptops were sold, so 80% were in the store.

So, after one month total number of laptops in the store,

\Rightarrow f(1)=0.8(150)+10

\Rightarrow f(1)=0.8(f(0))+10     (\because f(0)=150)

Again after one month total number of laptops in the store,

\Rightarrow f(2)=0.8\times (0.8(150)+10)+10

\Rightarrow f(2)=0.8(f(1))+10     (\because f(1)=0.8(150)+10)

Analyzing the pattern, the recursive function f(n) will be,

f(n)=0.8(f(n-1))+10,\ f(0)=150,\ \ n>0


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