Solution: We are given:

Let
be the weight (oz) of laptop
We have to find 
To find the this probability, we need to find the z score value.
The z score is given below:



Now, we have to find 
Using the standard normal table, we have:

0.9236 or 92.36% of laptops are overweight
30/40 Maybe I am guessing sorry if it is wrong Please mark me as brainliest
The answer the 3,
First you have to apply the exponent rule which is 1 - 3• 1/g
Then you multiply the fractions - 1•3/g
Then multiply the numbers 1 and 3, which is 3, so there you have it 3/g, or 3, they’re the same thing.
Answer:
9.57 inch
Step-by-step explanation:
(4/3)×pi×8³ = 14×16×h
h = (4/3)×pi×8³ ÷ (14×16)
h = 64pi/21 inch
Or, 9.57 inch (3 sf)