All categories

3 years ago

Which problems result in a positive number? Choose all answers that are correct. A. –4.6 • 1.6 B. –10 • (–5.2) C. 8.4 ÷ 2 D.

1 answer:

8 0

Well you can automatically eliminate, A, because when you multiply one number that's positive and another number that's negative the result is always going to be negative.
However, when you multiply two negatives the result is always positive!

So, the only ones up there that would result in a positive number is B and C

***D. was not posted so I cannot determine that one!

You might be interested in

whitney says that to add fractions with diffrent denominatros, you always have to multiply the denominators to find the common u

Ede4ka [16]

You could multiply 1/4 by 3 and 1/6 by 2. You would get 3/12 and 2/12. The common denomonator is 12. 4 and 6 are both multiples of 12.

4 0

4 years ago

Ariel, who is 15, is 3 years more than<br> twice the age of Hilary. How old is<br> Hilary?

antoniya [11.8K]

Answer:

Step-by-step explanation:

15 - 3 = 12, divide that by 2 and your answer is 6.

3 0

3 years ago

Дешовок в гавне собак гандонов свиней)))))))))) xddddddd

Readme [11.4K]

Step-by-step explanation:

jhggcxddddddddddddddddd

8 0

3 years ago

Read 2 more answers

What is the rate of change for the equation y = 0.860x + 3.302.?

dimaraw [331]

The rate of change is 0.860.

7 0

4 years ago

Read 2 more answers

How much should a family deposit at the end of every 6 months in order to have $4000 at the end of 3 years? The account pays 5.9

ra1l [238]

We are asked to determine the present value of an annuity that is paid at the end of each period. Therefore, we need to use the formula for present value ordinary, which is:

$PV_{ord}=C(\frac{1-(1+i)^{-kn}}{\frac{i}{k}})$

Where:

$\begin{gathered} C=\text{ payments each period} \\ i=\text{ interest rate} \\ n=\text{ number of periods} \\ k=\text{ number of times the interest is compounded} \end{gathered}$

Since the interest is compounded semi-annually this means that it is compounded 2 times a year, therefore, k = 2. Now we need to convert the interest rate into decimal form. To do that we will divide the interest rate by 100:

$\frac{5.9}{100}=0.059$

Now we substitute the values:

$PV_{ord}=4000(\frac{1-(1+0.059)^{-2(3)}}{\frac{0.059}{2}})$

Now we solve the operations, we get:

$PV_{\text{ord}}=39462.50$

Therefore, the present value must be $39462.50

8 0

2 years ago