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GalinKa [24]
3 years ago
13

What is the volume of the pyramid shown below?

Mathematics
2 answers:
ra1l [238]3 years ago
8 0
432 cu. units is the answer

Elodia [21]3 years ago
3 0

Answer:

B is the answer of this question

Step-by-step explanation:

144 cu. units

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P squared minus 4P minus 32 divided by p + 4
SSSSS [86.1K]

Answer:

X-8

Im not 100% sure but i think that is the answe

3 0
3 years ago
What is the second step to solve this x/2-5=1
sveta [45]

Answer:

X = -3

Step-by-step explanation:

X/2-5 = 1

X/-3 = 1

Multiply both sides by -3 to isolate x

X = -3

5 0
2 years ago
Mr. jovanovski is having wood flooring put in his rectangular living room. the area of the room is 234 square feet. the length o
OlgaM077 [116]
By definition the area of a rectangle is:
 A = l * w
 Where,
 l: long
 w: width
 So we have to clear the width:
 w = A / l
 Substituting the values:
 w = (234) / (18) = 13
 w = 13 feets
 answer
 the width, in feet, of the room is 13
5 0
3 years ago
Read 2 more answers
A square is folded into half to form a rectangle. the perimeter of the rectangle is 36cm. calculate the area of a square​
zhannawk [14.2K]

Answer:

Let the measure of each side of the square be " x " cm.

then ,

area of square = x²

After we folded the square into a rectangle ,

length of rectangle = x

breadth of rectangle = x/2

perimeter of rectangle = 36 cm

x +  \frac{x}{2}  + x +  \frac{x}{2}  = 36 \\  \\    \frac{2x + x + 2x + x}{2}  = 36 \\  \\   \frac{6x}{2}  = 36 \\  \\ 6x = 36 \times 2 \\  \\ 6x = 72 \\  \\ 6x =  \cancel{\frac{72}{6} } = 12cm

hence ,

side of square = 12 cm

therefore ,

area of square = 12 × 12 = 144 cm²

hope helpful~

8 0
2 years ago
The sum of a number and 20 is no more than the sum of the square of the number and 9.
aniked [119]

A is the correct answer.

break down the word problem.

You also have to recognize key words which figure into mathematical symbols.

ex. sum of a number and 20 is x+20

square of the number and 9 is (x+9)^2

please vote my answer brainliest! thanks.

5 0
3 years ago
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