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nata0808 [166]
3 years ago
7

WILL MARK BRAINLIEST !!!

Physics
1 answer:
Tresset [83]3 years ago
6 0

Answer:

P waves are a type of seismic wave that is characterized by being a longitudinal mechanical wave, which means that the medium through which they travel is alternately compressed and dilated in the<u> same direction of propagation</u>. This means they propagate in a similar way to the sound.

These waves are faster than the S waves, so when an earthquake occurs these waves <u>are the first to be recorded by the seismograph</u>. They can also travel through any type of material (solid, liquid or gaseous), this means they are able to <u>travel through solid rocks as well as in oceans or volcanic magma and are even able to be </u><u>transmitted through the atmosphere</u>, that is why they are sometimes perceived by people and animals as a deep sound.

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Explanation:

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Gold has a specific heat of 129 J/kg°C. How many joules of heat energy are required
ikadub [295]
To raise 1 kg by 1C, it will take 129 joules.

To raise 0.015 kg by (85-22)C, it will take (129*0.015)*22 = 42.57 joules.
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4 years ago
Which of the following pairings are more likely to be held together with the strong nuclear force?
aivan3 [116]

Which of the following pairings are more likely to be held together with the strong nuclear force

Explanation:

1.What does a strong nuclear force do in an atom? It repels electrons from other electrons. It repels protons from other protons. It attracts protons and neutrons.

2.The chain reaction requires both the release of neutrons from fissile isotopes undergoing nuclear fission and the subsequent absorption of some of these neutrons in fissile isotopes.

3.The strong nuclear force holds most ordinary matter together because it confines quarks into hadron particles such as the proton and neutron. In addition, the strong force binds these neutrons and protons to create atomic nuclei.

8 0
3 years ago
An aluminum wire with a diameter of 0.115 mm has a uniform electric field of 0.235 V/m imposed along its entire length. The temp
tekilochka [14]

Answer with Explanation:

We are given that

Diameter of coil=d=0.115mm

Radius, r=\frac{d}{2}=\frac{0.115}{2}=0.0575mm=0.0575\times 10^{-3} m

Using 1mm=10^{-3} m

Electric field=E=0.235V/m

T=55 degree C

T_0=20^{\circ} C

\rho_0=2.82\times 10^{-8}\Omega m

\alpha=3.9\times 10^{-3}/C

(a).We know that

\rho=\rho_0(1+\alpha(T-T_0))

Substitute the values

\rho=2.82\times 10^{-8}(1+3.9\times 10^{-3}(55-20))

\rho=3.2\times 10^{-8}\Omega m

(b).Current density,J=\frac{E}{\rho}

Using the formula

J=\frac{0.235}{3.2\times 10^{-8}}=7.3\times 10^6A/m^2

c.Total current,I=JA

Where A=\pi r^2

\pi=3.14

Using the formula

I=7.3\times 10^6\times 3.14\times (0.0575\times 10^{-3})^2

I=0.076A

d.Length of wire=l=2m

V=El

Substitute the values

V=0.235\times 2=0.47 V

5 0
3 years ago
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