Answer:
<em> The answer is </em><u><em>(D) Magnetism</em></u>
The methods separates a homogeneous solution by spinning the solution very fast is magnetism.
Answer: Secondary amines react with the nitrosonium ion to generate <span>
<u>N-Nitrosoamines</u>.
Explanation: Nitosonium Ion is generally utilized in the formation of
Diazonium Salts which are considered excellent starting Material from synthesis point of View. Diazonium salts are formed by reacting
Primary Amine or
Anilines with Nitrosonium Ions. In our case, the Amine given is Secondary. So, reaction of <em>Sec.</em> Amines with Nitrosonium Ions stops after the formation of N-Nitrosoamine as there is no Hydrogen attached to Nitrogen atom of Amine to be eliminated and form a double and eventually triple bond with the Nitrogen atom of Nitrosonium Ion.</span>
When the sugar cubes are <span>placed in water, then, the mixture will be affected by stirring the water.
By stirring the water, the sugar cubes dissolve in water. The molecules of sugar cubes interact with water molecules in the jar. But when more sugar is added to the water, there comes a saturation point when no more sugar will be dissolved and it will settle down. Then, by raising the temperature the settled sugar will be dissolved too.</span>
Answer is: empirical formula is H₄N₂O₂.
m(unknown compound) = 8,5 g.
m(N₂) = 2,37 g.m(H₂O) = 3,04 g.
n(N₂) = m(N₂) ÷ M(N₂).
n(N₂) = 2,37 g ÷ 28 g/mol.
n(N₂) = 0,0846 mol.
n(H₂O) = m(H₂O) ÷ M(H₂O).
n(H₂O) = 3,04 g ÷ 18 g/mol.
n(H₂O) = 0,168 mol.
n(H₂O) : n(N₂) = 0,168 mol : 0,0846 mol.
n(H₂O) : n(N₂) = 2 : 1.
Compound has four hydrogen, two oxygen and two oxygen.
Answer:
8.55 × 10³ cal
Explanation:
Step 1: Given and required data
- Specific heat of water (c): 1 cal/g.°C
- Initial temperature: 22.7 °C
- Final temperature: 38.8 °C
Step 2: Calculate the temperature change (ΔT)
ΔT = Final temperature - Initial temperature = 38.8 °C - 22.7 °C = 16.1 °C
Step 3: Calculate the heat required (Q)
We will use the following expression.
Q = c × m × ΔT
Q = 1 cal/g.°C × 531 g × 16.1 °C = 8.55 × 10³ cal