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kvv77 [185]
3 years ago
8

Which mixture would be easiest to separate based on the size of the particles? A. Oil and water B. Vinegar and water C. Sugar an

d water D. Sand and gravel.
Chemistry
1 answer:
Anna11 [10]3 years ago
6 0

Sand and gravel mixture would be easiest to separate based on the size of the particles.

<h3>What are mixtures?</h3>

Mixtures are the composition which can be obtained by the combination of different types of elements.

In the question different types of mixtures are given in which all have same kind of size distribution except sand and gravel. Size of sand is smaller than gravel, so it can be separated by easy physical method like sieving.  

Hence, option (d) is correct it means sand and gravel would be easiest to separate.

To know more about mixtures, visit the below link:

brainly.com/question/1917079

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If 20. 3 grams of an aqueous solution of iron(ii) chloride, fecl2, contains 2. 71 grams of iron(ii) chloride, what is the percen
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If 20. 3 grams of an aqueous solution of iron(ii) chloride contains 2. 71 grams of iron(ii) chloride, then percentage by mass of  iron(ii) chloride in the solution is 13.34%

Calculation,

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How much energy would be produced from the reaction of 2.40 moles hydrogen with 3.95 moles chlorine? ___ H2 + ___ Cl2 ___ HCl ΔH
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Answer:

How much energy would be produced from the reaction of 2.40 moles hydrogen with 3.95 moles chlorine?

H_2 +  Cl_2 -> 2HCl ,  deltaH = -554 kJ

Explanation:

Given,

2.40 moles hydrogen reacts with 3.95 moles chlorine.

From the balanced chemical equation,

1mol. of H2 reacts with 1mol. of Cl2

then,

2.40mol. of H2 reacts with ----?mol of Cl2

=>2.40 mol. H2 * \frac{1mol. Cl2}{1mol. H2} \\=2.40 mol. Cl2

So, the remaining moles of Cl2 is in excess.

The limiting reagent is--- H2.

1mol. of H2 releases --- 554kJ of energy

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