Answer:
Total area is 198.6cm²
Step-by-step explanation:
This problem bothers on the mensuration of flat shapes.
Step one
From the given figure the two semi circles left and right can be resolved as a whole (a complete circle) with diameter d 10cm
Radius r = 10/2= 5cm
Area of circle A= πr²
A= 3.142*5²
A= 3.142*25
A= 78.55
A= 78.6cm²
Step two
The remaining part of the shape is a rectangle with length (22-10)= 12cm
I.e the 10 is as a result of the radius of the two semi circles = r+r= 5+5=10
The rectangle has a width of 10cm
Area of rectangle A=12*10= 120cm²
Hence the total surface area of the shape
Total area = 120+78.6
Total area = 198.6cm²
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Answer:
x+2x+2=17
Step-by-step explanation:
I'm assuming that's what you're asking, so here is the answer explanation.
3x+6=21
3x=15
Hence, x=5
Apply x=5 to x+2x=2
5+10+2
=17
Answer:
a = 1
b = 3
c = 1
d = 2
e = 6
f = 8
Step-by-step explanation:
Any integer with power as zero = 1
<h3>
For a</h3>
2^x
2^0
= 1
<h3>
For b</h3>
3 * 2^x
3 * 2^0
3 * 1
= 3
<h3>
For c</h3>
2 ^ 3(x)
2 ^ 3(0)
2 ^ 0
= 1
<h3>For d</h3>
2^1
= 2
<h3>
For e</h3>
3 * 2^x
3 * 2^1
3 * 2
= 6
<h3>For f</h3>
2 ^ 3(x)
2 ^ 3(1)
2 ^ 3
2 * 2 * 2
= 8
Answer:
25%
Step-by-step explanation:
Great question, since a regular coin has two sides one heads and one tails. That gives us a 50% probability of it landing on either side of the coin. Since we would like to know the probability of getting 2 heads in a row, we would need to multiply the probability of the first toss landing on heads with the second toss landing on heads, like so...
So we can see that the probability of us getting two heads in a row is that of \frac{1}{4}[/tex] or 25%.
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