Answer:
b. 67
Step-by-step explanation:
In order for the average to be 62, the total of differences from 62 must be zero. The two given numbers have differences of -4 and -1, for a total of -5. In order for the total of differences to be zero, the third number must have a difference from 62 of +5. It must be 62+5 = 67.
Jon's height at his third checkup was 67 inches.
Based on the information given, the number of milligrams that will remain after 59 hours will be 13.125 milligrams.
Since after 40 hours, 25 mg of the substance has been removed, therefore, the rate per hour will be:
= 25/40 = 0.625.
The amount that will be removed in 59 hours will be:
= 59 × 0.625 = 36.875
The number of milligrams that will remain will be:
= 50 - 36.875 = 13.125 milligrams
Read related link on:
brainly.com/question/25776703
Seems to me like the question is: What are the two numbers ?
They have to multiply to 2,800 .
It's fairly easy to find two numbers that do that, BUT ...
they're not supposed to be multiples of 10 .
1 x 2,800 = 2,800 . . . . . No good. 2,800 is a multiple of 10 .
2 x 1,400 = 2,800 . . . . . No good. 1,400 is a multiple of 10 .
4 x 700 = 2,800 . . . . . No good. 700 is a multiple of 10 .
5 x 560 = 2,800 . . . . . No good. 560 is a multiple of 10 .
7 x 400 = 2,800 . . . . . No good. 400 is a multiple of 10 .
8 x 350 = 2,800 . . . . . No good. 350 is a multiple of 10 .
10 x 280 = 2,800 . . . . . No good. 280 is a multiple of 10 .
14 x 200 = 2,800 . . . . . No good. 200 is a multiple of 10 .
16 x 175 = 2,800 . . . . . Finally ! Neither one is a multiple of 10 .
Answer:
<em>The probability between 16.1 and 17.6 years = 0.0214 years </em>
<em>The Estimate probability between 16.1 and 17.6 years = 2.14 years</em>
<em>Step-by-step explanation:</em>
<u><em>Step(i)</em></u>:-
Given the average of Population 13.1 years
The standard deviation of the Population = 1.5 years
<em>Let 'x' be the random variable in Normal distribution</em>
<em>Given x = 16.1</em>


= 2
<em> Z₁ = 2</em>
<u><em>Step(ii):</em></u><em>-</em>
<em>Given x = 17.6</em>

<em> Z ₂= 3</em>
<em> Z₁ = 2 and </em> <em> Z ₂= 3 are both positive</em>
<em>The Estimate probability between 16.1 and 17.6 years</em>
<em>P( 16.1<x<17.6) = P( 2 < Z < 3)</em>
<em> </em> = A(3) - A(2)
= 0.49865 - 0.4772 (from normal table)
= 0.0214
<em>The probability between 16.1 and 17.6 years = 0.0214 years </em>
<em> = 0.0214 ×100 </em>
<em> = 2.14 years</em>
<u><em>Final answer</em></u><em>:-</em>
<em>The Estimate probability between 16.1 and 17.6 years = 2.14 years</em>
Answer:
11:05
Step-by-step explanation: