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Natalija [7]
3 years ago
10

Describe a real world situation between the area of a rectangle and its width, as the width varies and the length stays the same

sketch a graph to show this relationship
Mathematics
1 answer:
raketka [301]3 years ago
4 0
Area of rectangle = length x width If length is constant, say c and width is variable, say x Area of rectangle = y = cx This means Area will vary linearly with width and will represent a line with slope... hope I helped
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Please help me, if you help then thanks!
Vedmedyk [2.9K]

Answer:

1 / 2 is one side of the cube

Step-by-step explanation:

Take the cube root of 1/8 by taking the cube root of 1 which is 1 and then 8 which is 2 so equal to 1/2.

4 0
3 years ago
Quadrilateral ACEG≅ Quadrilateral MNPR<br><br> Which statement is true?
saul85 [17]
Line CE is congruent to line NP is the true statement.
4 0
4 years ago
A grocer sells 30 loaves of bread a day. The cost is $2.50 per loaf. The grocer estimates that for each $0.50 increase in cost,
Viktor [21]

Answer:

none of the above

Step-by-step explanation:

The grocer's revenue will be the product of the number of loaves sold (30-2x) and their price (2.50+0.50x).

Revenue will be positive for values of x between those that make these factors be zero. The number of loaves sold will be zero when ...

... 30 -2x = 0

... 15 -x = 0 . . . . . divide by 2

... x = 15 . . . . . . . add x

The price of each loaf will be zero when ...

... 2.50 +0.50x = 0

... 5 + x = 0 . . . . . . . multiply by 2

... x = -5 . . . . . . . . . . subtract 5

Revenue will be positive for any number of increases greater than -5 and less than 15.

_____

D is the best of the offered choices, but it is incorrect in detail. -5 is a number less than 15, but will give zero revenue.

4 0
4 years ago
Need help can anyone help me???​
Paladinen [302]

Answer:

  it is greater than 45°

Step-by-step explanation:

From the relationship of angles and secants/tangents, we have ...

  m∠GSO = (long arc GO -arc GT)/2

Solving for (long arc GO), we have ...

  2(m∠GSO) +arc GT = (long arc GO)

We know that (long arc GO) > 180°, so we can write ...

  2(m∠GSO) +90° > 180° . . . . arc GT = 90°

  2(m∠GSO) > 90° . . . . . . subtract 90°

  m∠GSO > 45° . . . . . . . . divide by 2

_____

<em>Alternate solution</em>

Inscribed ∠GOT has half the measure of arc GT, so is 45°.

You know that if angle G were 90°, then the right triangle would be isosceles, and angle S would also be 45°. In this triangle, arc GTO is less than 180°, so angle G is less than 90°.

When angle G gets smaller, the sum of angles remains the same, so angle S must be larger than 45°.

This reasoning is written more formally in the math above.

8 0
3 years ago
I need help :(( <br>.............................​
zepelin [54]

Answer:

a

Step-by-step explanation:

hope this helps

7 0
3 years ago
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