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Lesechka [4]
3 years ago
6

The formula for the rate at which water is flowing is R=v/t, where

Mathematics
1 answer:
Anarel [89]3 years ago
3 0
The answer is b I hope I could help
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Why does the term angle need to be defined prior to defining perpendicular lines?
igor_vitrenko [27]

Perpendicular lines<span> are two or more lines that intersect at a 90-degree angle, like the two lines drawn on this graph, and the x and y axes that orient them.</span>

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Plz help, i will give brainliest?<br><br> what is 890,754 x 205,789
nikdorinn [45]

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2 of a dozen eggs are cracked. What percent of the carton is NOT cracked using the percent proportion
levacccp [35]

If 2 of 12 eggs are cracked, then 10 are not cracked.

SO

10/12=5/6=about 0.83

0.83 of total eggs not cracked is also equivalent to 83 percent as asked in the problem :)

6 0
3 years ago
A company is to hire two employees. They have prepared a final list of eight candidates, all of whom are equally qualified. Of t
Softa [21]

Answer:

i) Probability that both candidates employed are women = 5/14

ii) Probability that the second candidate is a woman = 5/8

iii) Probability that the first candidate is a woman given that second one is a woman = 4/5

Step-by-step explanation:

Let the probability that a man is employed be P(M) = 3/8

Probability that a woman is employed P(W) = 5/8

a) Probability that both candidates employed are women = (5/8) × (4/7) = 5/14

b) Probability that the second candidate is a woman = (probability that first candidate is a man and second candidate is a woman) + (probability that first candidate is a woman & second candidate is a woman)

= (3/8)(5/7) + (5/8)(4/7) = (15/56) + (20/56) = 35/56 = 5/8

c) Probability that the first candidate is a woman given that second one is a woman

Given that the second candidate was a women, means that the first candidate-women was selected among other four women.

Probability = (4/8)/(5/8) = 4/5

7 0
3 years ago
Rewrite in simplest radical form 1 over x^(−3/6). Show each step of your process.
meriva

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\\\ ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}}

\bf \rule{34em}{0.25pt}\\\\ \cfrac{1}{x^{-\frac{3}{6}}}\implies x^{\frac{3}{6}}\implies x^{\frac{1}{2}}\implies \sqrt[2]{x^1}\implies \sqrt{x}

5 0
3 years ago
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