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svetlana [45]
2 years ago
15

The vertices of AJKL are J(-3, -2), K(1, 4), and L(4, 2). Which coordinate pairs are vertices of D5(^JKL)? Select all that apply

.
Mathematics
1 answer:
Alina [70]2 years ago
4 0

Given:

The vertices of ΔJKL are J(-3, -2), K(1, 4), and L(4, 2).

To find:

The coordinate pairs of vertices of D_5(\Delta JKL).

Solution:

We know that, D_5(\Delta JKL) means triangle JKL dilated by scale factor 5 with origin as center of dilation.

If a figure is dilated by factor k and origin is the center of dilation, then

(x,y)\to (kx,ky)

From the given problem, the rule of dilation is

(x,y)\to (5x,5y)

Now,

J(-3,-2)\to J'(5(-3),5(-2))=J'(-15,-10)

K(1,4)\to K'(5(1),5(4))=K'(5,20)

L(4,2)\to L'(5(4),5(2))=L'(20,10)

Therefore, the coordinate pairs of vertices of D_5(\Delta JKL) are J'(-15,-10), K'(5,20) and L'(20,10).

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lbvjy [14]

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5/9

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P ( any person wins no game in 4 attempts ) = ( 2/3 )^4 = 16/81

<em>Note : each player has equal chance of winning </em>

<u>Find the probability that there is at least one person who wins no games </u>

lets represent the probability of each player not wining a game with alphabet A

A1 = player 1 wins no game

A2 = player 2 wins no game

A3 = players 3 wins no game

Applying the inclusion-exclusion formula

<em>P( A1 ∪ A2 U A3 )</em><em> = P(A1 ) + P(A2) + P(A3) - P( A1 ∩ A2 ) - P( A2 ∩ A3 ) - P( A1            ∩ A3 )  + P( A1 ∩ A2 ∩ A3 ) </em>

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<u>SOLUTION:</u>

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