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svetlana [45]
3 years ago
15

The vertices of AJKL are J(-3, -2), K(1, 4), and L(4, 2). Which coordinate pairs are vertices of D5(^JKL)? Select all that apply

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Mathematics
1 answer:
Alina [70]3 years ago
4 0

Given:

The vertices of ΔJKL are J(-3, -2), K(1, 4), and L(4, 2).

To find:

The coordinate pairs of vertices of D_5(\Delta JKL).

Solution:

We know that, D_5(\Delta JKL) means triangle JKL dilated by scale factor 5 with origin as center of dilation.

If a figure is dilated by factor k and origin is the center of dilation, then

(x,y)\to (kx,ky)

From the given problem, the rule of dilation is

(x,y)\to (5x,5y)

Now,

J(-3,-2)\to J'(5(-3),5(-2))=J'(-15,-10)

K(1,4)\to K'(5(1),5(4))=K'(5,20)

L(4,2)\to L'(5(4),5(2))=L'(20,10)

Therefore, the coordinate pairs of vertices of D_5(\Delta JKL) are J'(-15,-10), K'(5,20) and L'(20,10).

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