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2 years ago

Please answer correctly !!!!!!!!! Will mark brainliest !!!!!!!!!!!

Mathematics

2 answers:

Olenka [21]2 years ago

8 0

Answer: no solutions

Step-by-step explanation:

There is no solutions because

the lines don't cross each other

Hope this helps :)

aalyn [17]2 years ago

5 0

Answer:

no solutions

Step-by-step explanation:

4x - 6y = -24

2x - 3y = -6

Multiply the second equation by -2

-4x +6y = 12

Add this to the first equation

4x - 6y = -24

-4x +6y = 12

------------------------

0 = -12

This is never true so there are no solutions

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8 A clock in the shape of an hour glass is made up of two identical cones

ra1l [238]

Answer:

The two cones are aligned on edge to edge so that the total volume of the hourglass becomes 2∗13πr2h

Step-by-step explanation:

a) When the sand has y units left in the upper cone the height of the cone becomes y, the radius remains 1cm.Now let's take the right triangle In the upper coneAnd by similar triangles property we found that the radius of the cone in which the amount of sand is left is y3 unitsNow the volume of the sand in the remaining part of the upper cone isπy32y which gives πy327Now if we apply the same similar triangle property with the cone in the below we find that the radius of the part it has filled up remains the same as y3unitsSo the volume it has filled is (3-y) from the top cone which says that the volume filled on the bottom cone has a height of (3-y)So therefore the volume of the frustum which it has filled up isπ3h(R2+r2+rR) {Is the volume of the frustum with two radii r and R with a height h}i.eπ3(3−y)(12+(y/3)2+(y/3))So now the total volume of the hourglass in terms of y is π3(3−y)(12+(y/3)2+(y/3))+πy327b) The next question tells us that when the height of the sand in the below cone reaches up a height of h centimetreswhich is exactly 3-y in the previous questionso substituting y = h-3 in the previous question we'll find the volume of the hourglass in terms of hπ(h−3)327+π3(6−h)(12+((h−3)/3)2+((h−3)/3)) .c) Total volume of the hourglass isV=V1+V2⇒3π4=πy327+π−π27(3−h)3Putting h=1We have the value of y as⇒3π4=π27y3+π+π278..............(1)⇒y=(54)13Differentiating the first equation with respect to t we have0=π9y2dydt+π9(3−h)2dhdtPutting values that dydt=−0.14inches/sec at h =1 and for ⇒y=(54)13We have0=π9(54)132∗(−0.14)+π922dhdt⇒0.1956π9=4π9dhdt⇒dhdt=0.19564⇒dhdt=0.0489

4 0

1 year ago

Edward is driving a car on the highway. He drives for 28.5 miles in 3/8 of an hour. At this rate, how much distance can he cover

Rom4ik [11]

The distance covered in one hour is 76 miles.

Step-by-step explanation:

Edward drives a car for 28.5 miles.

Therefore, the distance he travels by the car = 28.5 miles.

The time it takes to drive 28.5 miles is 3/8 of an hour.

The formula to find the rate :

Rate = Distance traveled / Time taken in hours.

Here, the distance is 28.5 miles and time is 3/8 hour.

Rate = $28.5/ (3/8)$

To find the distance covered in 1 hour :

Let us assume, 'x' be the distance covered in one hour.

Rate = $x/1$

Now, comparing the rates to find the x value :

⇒ $28.5 / (3/8) = x /1$

⇒ $x = 28.5 \times 8/3$

⇒ $x = 228/3$

⇒ $x = 76$

Therefore, the distance covered in one hour is 76 miles.

4 0

2 years ago

7(x-3)+6=5x-9 please solve the equation fully

TiliK225 [7]

Answer:

I love algebra anyways

The ans is x=3 steps is in the picture with the ans

(hope this helps can i plz have brainlist :D hehe)

Step-by-step explanation:

4 0

2 years ago

What dose 5h-2+9h equal explain☺

DerKrebs [107]

Start out by combining LIKE TERMS
5h-2+9h
in this case 9h and 5h are like terms so you would add both of those together.
9h+5h=14h
-2 has no like terms so we can't do anything with it our final answer would be:
14h-2

8 0

3 years ago

A line has a slope of –3 and a y-intercept of (0, –1). What is the equation of the line that is parallel to the given line and p

givi [52]

Well, the first line has a slope of -3, and runs through 0, -1.

a line parallel to that one, will have the same exact slope of -3.

now, we know about this other parallel line that it runs through -3,1, and of course, since is parallel, it has a slope of -3

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1\\
&&(~ -3 &,& 1~)
\end{array}
\\\\\\
% slope = m
slope = m\implies -3
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-1=-3[x-(-3)]
\\\\\\
y-1=-3(x+3)
\implies 
y-1=-3x-9\implies y=-3x-8$

6 0

3 years ago