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2 years ago

Find the product of 6/9 and 3/8 . Express your answer in simplest form.A.6/24 B.1/6 C.18/72 D.1/4

Mathematics

2 answers:

leonid [27]2 years ago

8 0

Answer:

D.) 1/4

Step-by-step explanation:

6/9 x 3/8

6(3) /8(9)

= 18/72

18/18=1

72/18=4

= D.) 1/4

Vikki [24]2 years ago

8 0

Answer:

D. 1/4

Step-by-step explanation:

First, we will multiply the numerator 6 × 3 = 18. Then, we'll multiply the denominators, 9 × 8 = 72. Then, divide 18 ÷ 18 = 1 and 72 ÷ 18 = 4. So there we go. the numerator is 1 and the denominator is 4. So the answer is 1/4 which is a proper fraction :) (mark this answer brainliest plz )

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SOVA2 [1]

Answer:

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Step-by-step explanation:

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2 years ago

Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e^−2

Mekhanik [1.2K]

Answer:

x=1

y=s

z=1

Step-by-step explanation:

(x, y, z)=(1, 0, 1)

Substitute 0 for y

$y = e^{-2t} *sin 4t\\0 = e^{-2t} *sin 4t\\\\0 = e^{-2t} *(\frac{e^{4t}-e^{-4t}}{2j} )\\0 = e^{-2t} *(e^{4t}-e^{-4t} )\\0 = e^{-2t} *e^{4t}*(1-e^{-8t} )\\\\0 = e^{2t}*(1-e^{-8t} )\\\\\\Either \\0 = e^{2t}\\t = -inf\\or\\0 = (1-e^{-8t} )\\(e^{-8t} ) = 1\\ -8t = ln(1) =0\\t=0\\\\$

Confirming if t=0 satisfy the other equation

x = e^−2t cos 4t = e^−2(0)cos(4*0)

= e^(0)cos(0) = 1

z = e^−2t = e^−2(0) = 0

Therefore t=0 satisfies the other equation

Finding the tangent vector at t=0

$\frac{dx}{dt}=-2te^{-2t} cos4t + e^{-2t}(-4sin4t)=-2(0)e^{-2(0)} cos4(0) + e^{-2(0)}(-4sin4(0))=0\\\\ \frac{dy}{dt} =-2te^{-2t} sin4t + e^{-2t}(4cos4t)=-2(0)e^{-2(0)} sin4(0)+ e^{-2(0)(4cos4(0)) }= 1\\\\\frac{dz}{dt} = -2te^{-2t} = -2(0)e^{-2(0)} = 0$

The vector equation of the tangent line is

(1, 0, 1) +s(0,1,0)= (1, s, 1)

The parametric equations are:

x=1

y=s

z=1

6 0

2 years ago

1 3/8 + 4 1/6 jwbhcjhbnegggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggg

Ilya [14]

BOIII get outta here

3 0

2 years ago

Read 2 more answers

ou decide to bake some cakes. You need 150 g of flour for 12 cakes. How much flour do you need for 30 cakes? g

Brilliant_brown [7]

Short answer: 375 grams

Remark
You only need to set up a direct proportion

Givens
flour for 12 cakes = 150 grams
Number of cakes initially = 12
Amount of flouer for 30 cakes = x
Number of cakes = 30

Proportion
amount flour for 12 cakes / 12 cakes = x / 30

Sub and solve
150 grams / 12 cakes = x / 30 cakes Cross multiply
150 * 30 = 12 *x Multiply the left side.
4500 = 12 x Divide both sides by 12
4500/12 = x
375 grams for 30 cakes. <<<<< Answer

5 0

2 years ago

For a school fundraiser mai will make school spirit bracelets. She will order bead wiring and alphabet beads to create the schoo

Andreas93 [3]

Answer:

235 bracelets

Step-by-step explanation:

Mai must spend $250 on wire and $5.30 per bracelet beads. Mai creates the expression.

We are given the equation:

5.3n+ 250 to represent the cost of making n bracelets.

The maximum number of bracelets Mai can make with a budget of $1500 Is calculated as:

$1500 = 5.3n+ 250

Collect like terms

1500 - 250 = 5.3n

1250 = 5.3n

n = 1250/5.3

n = 235.8490566 bracelets.

Bracelets are created as whole numbers and they can't be in decimal form.

Therefore, the maximum number of bracelets Mai can make with a budget of $1500 is 235 bracelets.

6 0

2 years ago