The area of a regular hexagon is
... A = (3√3)/2×s² . . . . . where s is the side length
Of course, the 6-sided figure will have a side length that is 1/6 of the perimeter.
... s = (48 in)/6 = 8 in
... A = (3√3)/2×(8 in)² = 96√3 in² . . . area of your regular hexagon
1 over 3 should be the answer I think
Answer:
Are a pair of angles on the outer side of each of those two lines but on opposite sides of the transversal.
Answer:
I don't think so
Step-by-step explanation:
but I'll try
