Can someone help pls

What is equivalent to (4xy-3z)^2 and what type of special product is it?

sergey [27]

Answer:

the answer on edgenuty is option D

Step-by-step explanation:

i just took the quiz

3 0

3 years ago

Find the slope of the line that passes through (3,1) (4,9)

pickupchik [31]

Answer:

+8

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Heidi spent a total of $60 on clothing items she bought 2 pairs of shorts for 10 dollars each she bought some t-shirts for 4 eac

lisov135 [29]

Answer:

2 pair shorts and for t-shirts and sandals possible cases are

1 t-shirt and 3 sandals or

4 t-shirts and 2 sandals or

7 t-shirts and 1 sandals.

Step-by-step explanation:

Total money spent by Heidi on the clothing items is $60.

Now , she bought 2 pairs of short for $10 each , so, the money spent on shorts will be $20.

Thus money for other stuffs should be $40.

Let she bought x t-shirts for $4 each , thus money spent on t-shirts will be 4x dollars.

Also let she bought y sandals for $12 each , so money spent on sandals will be 12y dollars .

Thus , 4x + 12y = 40. (since 40 dollars were remaining for other clothing

items)

So, x + 3y = 10.

So, the possible cases are 1 t-shirt and 3 sandals or

4 t-shirts and 2 sandals or

7 t-shirts and 1 sandals.

7 0

2 years ago

Giving 100 points.

Nitella [24]

Answer:

1. Cost per customer: 10 + x

Average number of customers: 16 - 2x

$\textsf{2.} \quad -2x^2-4x+160\geq 130$

3. $10, $11, $12 and $13

Step-by-step explanation:

Given information:

$10 = cost of buffet per customer
16 customers choose the buffet per hour
Every $1 increase in the cost of the buffet = loss of 2 customers per hour
$130 = minimum revenue needed per hour

Let x = the number of $1 increases in the cost of the buffet

Part 1

Cost per customer: 10 + x

Average number of customers: 16 - 2x

Part 2

The cost per customer multiplied by the number of customers needs to be at least $130. Therefore, we can use the expressions found in part 1 to write the inequality:

$(10 + x)(16 - 2x)\geq 130$

$\implies 160-20x+16x-2x^2\geq 130$

$\implies -2x^2-4x+160\geq 130$

Part 3

To determine the possible buffet prices that Noah could charge and still maintain the restaurant owner's revenue requirements, solve the inequality:

$\implies -2x^2-4x+160\geq 130$

$\implies -2x^2-4x+30\geq 0$

$\implies -2(x^2+2x-15)\geq 0$

$\implies x^2+2x-15\leq 0$

$\implies (x-3)(x+5)\leq 0$

Find the roots by equating to zero:

$\implies (x-3)(x+5)=0$

$x-3=0 \implies x=3$

$x+5=0 \implies x=-5$

Therefore, the roots are x = 3 and x = -5.

Test the roots by choosing a value between the roots and substituting it into the original inequality:

$\textsf{At }x=2: \quad -2(2)^2-4(2)+160=144$

As 144 ≥ 130, the solution to the inequality is between the roots:

-5 ≤ x ≤ 3

To find the range of possible buffet prices Noah could charge and still maintain a minimum revenue of $130, substitute x = 0 and x = 3 into the expression for "cost per customer.

[Please note that we cannot use the negative values of the possible values of x since the question only tells us information about the change in average customers per hour considering an increase in cost. It does not confirm that if the cost is reduced (less than $10) the number of customers increases per hour.]

Cost per customer:

$x =0 \implies 10 + 0=\$10$

$x=3 \implies 10+3=\$13$

Therefore, the possible buffet prices Noah could charge are:

$10, $11, $12 and $13.

8 0

1 year ago

3m-2n+4p=15 m-n+p=3 m+4n-5p=0

Viefleur [7K]

What you need help in

6 0

3 years ago