Using law of cosines and we will see that it is false.
Correct degree is approximately 48.77
We need Vector ST which is just T - S
(7-3.4-2) = (4,2)
So now we need the perpindicular. The easiest way to do this, is to know that , in R2 that the perindicular is just the negatice inverse. So its (2,-4)
Answer:
-19. Cant be -6 as its to the right. the others are positive.
i cant tell you that it is from a test
