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slavikrds [6]
3 years ago
5

Need help plz and thnks

Mathematics
1 answer:
Serjik [45]3 years ago
3 0

Answer: y=13

hope this helps!

You might be interested in
200-[(50-4)×3+5]<br><img src="https://tex.z-dn.net/?f=200%20-%20%28%2850%20-%204%29%20%5Ctimes%203%20%2B%205%29" id="TexFormula1
lbvjy [14]
200 - [ ( 50 - 4 ) × 3 + 5 ]
= 200 - [ 46 × 3 + 5 ]
<Put brackets around the 2 number that enclose the times sign as a reminder to do that first>
= 200 - [ ( 46 × 3 ) + 5 ]
= 200 - [ 138 + 5 ]
= 200 - (143)
= 57

Hope this helps!
3 0
3 years ago
Please help and thank you
kondaur [170]

Answer:

Step-by-step explanation:

Let's see how well I can explain this. \frac{\pi}{6} is the same as a 30 degree angle which is in quadrant 1. If you picture the unit circle, right in the center of it is the origin. If you draw a straight line from 30 degrees and through the center (the origin), you will automatically "connect" with the reference angle of 30 (this is true for ALL angles on the unit circle). This puts us in quadrant 3. In quadrant 3, x is negative and so is y. So the terminal point of the reference angle for 30 degrees has the same exact values, but both of them are negative (again, because both x and y are negative in quadrant 3). I can't see your choices but the one you want looks like this:

(-\frac{\sqrt{3} }{2},-\frac{1}{2})

3 0
3 years ago
Can someone help me with this? Thank you!
satela [25.4K]
The correct answer should be the third option. YOU'RE WELCOME :D
3 0
3 years ago
7th grade math help meee plzzzz
ale4655 [162]

Answer:

-18.4 + 35.4

Step-by-step explanation:

Use the method keep; change; flip.

Keep the negative -18.4

Change the minus sign to a plus sign

Flip the -35.4 to a positive 35.4

Even though the equations are different the answer is still the same.

Hope this helps!

8 0
3 years ago
The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d
jek_recluse [69]

Answer:

50%

Step-by-step explanation:

68-95-99.7 rule

68% of all values lie within the 1 standard deviation from mean (\mu-\sigma,\mu+\sigma)

95% of all values lie within the 1 standard deviation from mean  (\mu-1\sigma,\mu+1\sigma)

99.7% of all values lie within the 1 standard deviation from mean  (\mu-3\sigma,\mu+3\sigma)

The distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4.

\mu = 55\\\sigma = 4

68% of all values lie within the 1 standard deviation from mean (\mu-\sigma,\mu+\sigma) = (55-4,55+4)= (51,59)

95% of all values lie within the 2 standard deviation from mean  (\mu-1\sigma,\mu+1\sigma)= (55-2(4),55+2(4))= (47,63)

99.7% of all values lie within the 3 standard deviation from mean  (\mu-3\sigma,\mu+3\sigma)= (55-3(4),55+3(4))= (43,67)

Refer the attached figure

P(43<x<55)=2.5%+13.5%+34%=50%

Hence The approximate percentage of light bulb replacement requests numbering between 43 and 55 is 50%

4 0
3 years ago
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