W + 3 3/8 = 1 5/6;
W = 1 5/6 - 3 3/8;
W = 11/6 - 27/8;
W = 11/(2*3) - 27/(2*4);
W = (11*4 - 27*3)/(2*3*4);
W = (44 - 81)/24;
W = -37/24 = -1 13/24;
Answer:
6.11km/hr
Step-by-step explanation:
Let the speed that Kelli swims be represented by Y
Speed of the river = 5km/hr
Distance = Speed × Time
Kelli swam upstream for some distance in one hour
Swimming upstream takes a negative sign, hence:
1 hour ×( Y - 5) = Distance
Distance = Y - 5
She then swam downstream the same river for the same distance in only 6 minutes
Downstream takes a positive sign
Converting 6 minutes to hour =
60 minutes = 1 hour
6 minutes =
Cross Multiply
6/60 = 1/10 hour
Hence, Distance =
1/10 × (Y + 5)
= Y/10 + 1/2
Equating both equations we have:
Y - 5 = Y/10 + 1/2
Collect like terms
Y - Y/10 = 5 + 1/2
9Y/10 = 5 1/2
9Y/ 10 = 11/2
Cross Multiply
9Y × 2 = 10 × 11
18Y = 110
Y = 110/18
Y = 6.1111111111 km/hr
Therefore, Kelli's can swim as fast as 6.11km/hr still in the water.
Answer:yes
Step-by-step explanation:Bc I am right and right
<u>Answer-</u>
<em>The probability of winning on the first roll is </em><em>0.22</em>
<u>Solution-</u>
As in the game of casino, two dice are rolled simultaneously.
So the sample space would be,
Let E be the event such that the sum of two numbers are 7, so
E = {(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}
Let F be the event such that the sum of two numbers are 11, so
F = {(6,5), (5,6)}
Now,
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