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Nataliya [291]
2 years ago
8

Find the zeros of the function f(x)=3x^2-27

Mathematics
1 answer:
Inessa05 [86]2 years ago
4 0

3x^2-27=0\\3x^2=27\\x^2=9\\x=-3 \vee x=3

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B2x%2B4%7D%7Bx%5E%7B2%7D-2x-8%20%7D" id="TexFormula1" title="\frac{2x+4}{x^{2}-2x-8 }
lisabon 2012 [21]

Answer:

\frac{2}{x-4}

Step-by-step explanation:

\frac{2x+4}{x^2-2x-8}

Factor both the numerator and denominator

\frac{2(x+2)}{(x-4)(x+2)}

The x+2 's cancel out

The equation in its simplest form is \frac{2}{x-4}

Hope this helps!

6 0
3 years ago
Use the quotient of negative numbers:
strojnjashka [21]
If you divide negative by positive it will be negative.
If you divide positive by negative it will be negative.
If you divide 2 negatives you get a positive.
I hope this helps :)
4 0
4 years ago
A bag of apples weighs 7 2/7
photoshop1234 [79]

Answer:

43.71428571

Step-by-step explanation:

First, convert 7 2/7 into an improper fraction: 51/7

Second, multiply 51/7 by 5: 255/7

Third, add 255/7 and 51/7 to get 306/7

306/7 = 43.71428571

6 0
3 years ago
Find the prime factorization of 36
ivolga24 [154]

Prime factorization means finding the prime numbers that you can multiply to make a certain number.

So, he prime factorization of 36 would be 2 x 2 x 3 x 3   or   2, 2, 3, and 3.

Just to make sure:    2 x 2 = 4    4 x 3 = 12     12 x 3 = 36

There's your answer!

7 0
3 years ago
Let omega be a complex number such that omega^3 = 1. Find all possible values of {1}{1 + \omega} + {1}{1 + \omega^2}. Enter all
Norma-Jean [14]

Answer:

1 is Answer.

Step-by-step explanation

\frac{1}{1+omega^{2} } + \frac{1}{1+omega }\\

= \frac{(-1)*(omega + 1)}{omega^{2}  }

As we know that ω²+ω+1=0

Thus putting in above equation, we get

= \frac{1}{(-1)*omega } + \frac{1}{(-1)*omega^{2}  }

Rearranging and simplifying:

= \frac{-1}{omega } + \frac{-1}{omega^{2}  }

= \frac{(-1)*(omega + 1)}{omega^{2}  }

= \frac{(-1)*(- omega^{2} )}{omega^{2}  }

= 1 Answer

8 0
3 years ago
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