<h2>Answer: 250 Hamburgers sold</h2><h2>Step-by-step explanation:</h2><h2><u><em>x = hamburgers
</em></u></h2><h2><u><em>y = cheeseburgers
</em></u></h2><h2><u><em>x+y=434
</em></u></h2><h2><u><em>66 fewer cheeseburgers than hamburgers
</em></u></h2><h2><u><em>
</em></u></h2><h2><u><em> </em></u></h2><h2><u><em>y = x - 66
</em></u></h2><h2><u><em>Substitute y into the first equation
</em></u></h2><h2><u><em>x + (x-66) = 434
</em></u></h2><h2><u><em>2x = 434 + 66
</em></u></h2><h2><u><em>2x = 500
</em></u></h2><h2><u><em>x = 250 hamburgers sold</em></u></h2>
Answer:
False
Step-by-step explanation:
13 ≤ 4n if n = 3
13 ≤ 12
Is this true?
First of all this symbol (≤) means
- Less than
- Equal to
Is 13 less than 12?
No
Is 13 equal to 12?
No
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
-Chetan K
Answer:
b = 14-4
Step-by-step explanation:
Let the number of black bugs be b
Let the number of green bugs be g
If 14 bugs are crawling on the step, then;
b + g = 14 ....1
If there are 4 green bugs, then g = 4
Substitute g = 4 into the equation
b + g = 14
b + 4 = 14
b = 14 - 4
Hence the sentence that can be required to find the number of black bugs is b = 14-4
Answer:
Keenan's z-score was of 0.61.
Rachel's z-score was of 0.81.
Step-by-step explanation:
Z-score:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Keenan scored 80 points on an exam that had a mean score of 77 points and a standard deviation of 4.9 points.
This means that
So
Keenan's z-score was of 0.61.
Rachel scored 78 points on an exam that had a mean score of 75 points and a standard deviation of 3.7 points.
This means that . So
Rachel's z-score was of 0.81.