3 years ago

Im struggling, someone please help, thankyou :)

Mathematics

1 answer:

xxMikexx [17]3 years ago

8 0

There are 18 silver coins in the box.

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Solve for a.<br> a^2=-3a+88

Sergio [31]

Answer:

$a=8,-11$

Step-by-step explanation:

$a^2=-3a+88$

$a^2+3a=88$

$a^2+3a-88=0$

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

$x=\frac{-3\pm\sqrt{3^2-4(1)(-88)} }{2(1)}$

$x=\frac{-3\pm\sqrt{9+352} }{2}$

$x=\frac{-3\pm\sqrt{361} }{2}$

$x=\frac{-3\pm19 }{2}$

$x=-11$ and $x=8$

Therefore, the values of $a$ are 8 and -11.

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Irina18 [472]

Answer:

D. (2 , 0)

Step-by-step explanation:

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(2 , -3) -> (2 , -3+3) -> (2 , 0)

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2 years ago

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bija089 [108]

Answer:

i think its 4,800

Step-by-step explanation:

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Step-by-step explanation:

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x = 0.75

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ladessa [460]

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