A=g
v=⌠g dt
v=gt+C, where C=v initial
v=gt+vi
h=⌠v dt
h=gt^2/2+vit+C, where C=h initial
h=gt^2/2+vit+hi
We are told that vi=42 ft/s, hi=0, and we know g≈-32 ft/s^2 so
h(t)=-16t^2+42t
The ball will hit the ground when h=0 so
-16t^2+42t=0
-2t(8t-21)=0, since t>0
8t-21=0
8t=21
t=21/8
t=2.625 sec
t≈2.6 sec (to nearest tenth of a second)
Let's take the number as x.
two-fifths of a number = 2x / 5
decreased by 3 = (2x/5) - 3
(2x/5) - 3
(2*25/5) - 3
(2*5) - 3
10 - 3
7
Answer:
1.4 times as long
Step-by-step explanation:
3 1/2 (convert to mixed number) --> 7/2
2 1/2 (convert to mixed number) --> 5/2
(7/2) / (5/2) --> 7/5 --> 1.4
If you want to find the volume, multiply the area of the base by the height. In this problem it would be 888*555, which is equal to 492,840
