What is the lateral surface area of a cylindrical-shaped candle with a radius of 4 cm and a height of 14 cm? (Use 3.14 for pi .)

Which statement is true about the graphs of the two lines and ? y= -8x -5/4 and y = 1/8x + 4/5

Ronch [10]

Y = -8x - 5/4......slope here is -8 or -8/1
y = 1/8x + 4/5...slope here is 1/8

what u have here are negative reciprocal slopes....negative reciprocal of a number can be found by flipping the number and changing the sign. So the negative reciprocal of -8/1 is 1/8 (see how I flipped the number and changed the sign)...and when u have negative reciprocal slopes, this means that ur lines are perpendicular.

7 0

3 years ago

What is the common ratio for the sequence:<br> 28, -14, 7, -3.5...

Setler79 [48]

1/2,-1/2 is the answer

6 0

2 years ago

Explain why each of the following integrals is improper. (a) 4 x x − 3 dx 3 Since the integral has an infinite interval of integ

erma4kov [3.2K]

Answer:

a

Since the integral has an infinite discontinuity, it is a Type 2 improper integral

b

Since the integral has an infinite interval of integration, it is a Type 1 improper integral

c

Since the integral has an infinite interval of integration, it is a Type 1 improper integral

d

Since the integral has an infinite discontinuity, it is a Type 2 improper integral

Step-by-step explanation:

Considering a

$\int\limits^4_3 {\frac{x}{x- 3} } \, dx$

Looking at this we that at x = 3 this integral will be infinitely discontinuous

Considering b

$\int\limits^{\infty}_0 {\frac{1}{1 + x^3} } \, dx$

Looking at this integral we see that the interval is between $0 \ and \ \infty$ which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral

Considering c

$\int\limits^{\infty}_{- \infty} {x^2 e^{-x^2}} \, dx$

Looking at this integral we see that the interval is between $-\infty \ and \ \infty$ which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral

Considering d

$\int\limits^{\frac{\pi}{4} }_0 {cot (x)} \, dx$

Looking at the integral we see that at x = 0 cot (0) will be infinity hence the integral has an infinite discontinuity , so it is a Type 2 improper integral

7 0

3 years ago

John is buying a TV that costs $1250. He currently has $200 saved and is

Angelina_Jolie [31]

It will take him 21 weeks to have $1250 saved

7 0

3 years ago

Read 2 more answers

Which equation has no solution?

san4es73 [151]

Answer:

c

Step-by-step explanation:

hope this helps

4 0

2 years ago