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Alexxandr [17]
2 years ago
11

Given that

Mathematics
1 answer:
NeX [460]2 years ago
6 0

Answer:

R = 4x + 8y

-8y = 4x - R

-8y = 4(4) - 32

-8y = 16 - 32

-8y = -16

we divide through by -8

so now

y = 2

Hope this will help

You might be interested in
Determine the equation of the tangent line to the given path at the specified value of t. (sin(7t), cos(7t), 2t9/2); t=1
Reptile [31]

Answer:

P(t) = {sin7, cos7, 2} + (7cos7, -7sin7, 9)(t-1)

Step-by-step explanation:

The equation of the tangent line to the given path at the specified value of t is expressed as;

P(t) = f(t0) + f'(t0)(t - t0)

f(t0) = (sin(7t), cos(7t), 2t^9/2)

at t0 = 1;

f(t0) = {sin7(1), cos7(1), 2(1)^9/2}

f(t0) = {sin7, cos7, 2}

f'(t0) = (7cos7t, -7sin7t, 9/2{2t^9/2-1}

f'(t0) = (7cos7t, -7sin7t, 9t^7/2}

If t0 = 1

f'(1) = (7cos7(1), -7sin7(1), 9(1)^7/2)

f'(1) =(7cos7, -7sin7, 9)

Substituting the given function into the tangent equation will give:

P(t) = f(t0) + f'(t0)(t - t0)

P(t)= {sin7, cos7, 2} + (7cos7, -7sin7, 9)(t-1)

The final expression gives the equation of the tangent line to the path.

4 0
3 years ago
Step by step PLEASE!!!
blondinia [14]
F(x) = 3x^2+6x-2

= 3(x^2+2x-2/3)
= 3(x^2 +2x + 1 - 1 - 2/3)
= 3((x+1)^2 - 1 - 2/3)
= 3((x+1)^2 -5/3))
= 3(x+1)^2 - 5

So our function is in the form:

f(x) = 3(x+1)^2 - 5
where a = 3, h = -1, k = -5
7 0
3 years ago
Solve: |x+2|−1≥5. Write your solution in interval notation.
AlekseyPX

nswer:

Step-by-step explanat

|x+2| - 1 ≥ 5

  |x+2|  ≥ 5+1

 |x+2|  ≥ 6

 x+2 ≥ 6 hoặc x+2 ≤ -6

+ với x+2 ≥ 6  x ≥ 6 – 2   x ≥ 4

+ với x+2 ≤ -6  x ≤ -6 – 2  x ≤ -8

(-∝;-8)∪(4;+∝)

6 0
2 years ago
Pls help will give brainliest to the right answer :)
morpeh [17]

Answer:

62

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Which number line models the sum of 1+(−2) correctly?
Tomtit [17]

Answer:

option 3

Step-by-step explanation:

you add one, so the arrow goes one space to 1

since youre sutracting -2, the arrow goes ack two spaces to -1

7 0
3 years ago
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