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2 years ago

5

Vince weighs 160 pounds, and his friend Nadir weighs 140 pounds. Nadir calculated that his weight on another planet would be abo

ut 56 lb. Approximately what would Vince weigh on the other planet?
40 lb
64 lb
76 lb
90 lb

2 answers:

Mila [183]2 years ago

6 0

Answer:

64lb

Step-by-step explanation:

i mean i got it right on my quiz on egde 2020

Ymorist [56]2 years ago

4 0

Answer: 64 lbs

Step-by-step explanation:

I divided 56/140 and got 0.4. Then multiplied 0.4 by 160 and got 64. SOunds about right to me.

You can double check by multipling 0.4 by 140 and you get 56.

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Roll the number cube to find the observed frequency. Which statements are true? Check all that apply

ch4aika [34]

Answer:

(a) and (c)

Step-by-step explanation:

Given

See attachment for complete question

Required

Select all true statements

First, calculate the total observed frequency;

$Total = 11 + 16 + 14 + 20 + 12 + 17$

$Total = 90$

<u>(a): Relative frequency of 4 is 2/9</u>

Relative frequency is calculated by:

$RF= \frac{Observed\ Frequency}{Total}$

For roll 4

$Observed\ frequency = 20$

So, the relative frequency is:

$RF = \frac{20}{90}$

Simplify

$RF = \frac{2}{9}$

<em>(a) is true</em>

<u>(b): Experimental probability of 3 greater than its theoretical probability</u>

The experimental probability is its relative frequency;

For roll 3

$Observed\ frequency = 14$

The experimental probability is:

$Pr = \frac{14}{90}$

Simplify

$Pr = \frac{7}{45} = 0.156$

To calculate the theoretical probability, w have:

$S = \{1,2,3,4,5,6\}$ ---- sample space

$n(S)= 6$

$n(3) = 1$ --- number of times 3 occur

The theoretical probability is:

$Pr = \frac{1}{6} = 0.167$

The theoretical probability is $greater\ than\ the$ experimental probability.

<em>(b) is false</em>

<u>(c): Experimental probability of 2 greater than its theoretical probability</u>

Using the explanations in (b), we have:

For roll 2

$Observed\ frequency = 16$

The experimental probability is:

$Pr = \frac{16}{90}$

Simplify

$Pr = \frac{8}{45} = 0.178$

To calculate the theoretical probability, we have:

$n(S)= 6$

$n(2) = 1$

The theoretical probability is:

$Pr = \frac{1}{6} = 0.167$

The experimental probability is $greater\ than\ the$ theoretical probability.

<em>(c) is true</em>

<u>(d): Relative frequency of 5 is 2/13</u>

For roll 5

$Observed\ frequency = 12$

The relative frequency is:

$RF = \frac{12}{90}$

Simplify

$RF = \frac{2}{15}$

<em>(d) is true</em>

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