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Trava [24]
2 years ago
5

Vince weighs 160 pounds, and his friend Nadir weighs 140 pounds. Nadir calculated that his weight on another planet would be abo

ut 56 lb. Approximately what would Vince weigh on the other planet?
40 lb
64 lb
76 lb
90 lb
Mathematics
2 answers:
Mila [183]2 years ago
6 0

Answer:

64lb

Step-by-step explanation:

i mean i got it right on my quiz on egde 2020

Ymorist [56]2 years ago
4 0

Answer: 64 lbs

Step-by-step explanation:

I divided 56/140 and got 0.4. Then multiplied 0.4 by 160 and got 64. SOunds about right to me.

You can double check by multipling 0.4 by 140 and you get 56.

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If 12 &gt; -15, which of the following must be true?
Tcecarenko [31]

Answer:

12 is to the right of -15 on a number line.

Step-by-step explanation:

Hope this helps! - CJ

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3 years ago
Solve the inequality and show your solution on a number line: −4x≥−1
kiruha [24]

<em>*To solve an inequality, it's the same as solving an equation; isolate the variable to one side.</em>

For this, all you need to do is divide both sides by -4. And since we are dividing by a <u>negative</u>, flip the inequality sign and your inequality is x\leq\frac{1}{4}

Now to graph this. Since x can be "equal to" 1/4 ( ≤ = less than or equal to), you will have a <u>closed circle on 1/4.</u> And since x can also be "less than" 1/4, <u>the arrow will be going to the left of 1/4.</u>

6 0
3 years ago
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Roll the number cube to find the observed frequency. Which statements are true? Check all that apply
ch4aika [34]

Answer:

(a) and (c)

Step-by-step explanation:

Given

See attachment for complete question

Required

Select all true statements

First, calculate the total observed frequency;

Total = 11 + 16 + 14 + 20 + 12 + 17

Total = 90

<u>(a): Relative frequency of 4 is 2/9</u>

Relative frequency is calculated by:

RF= \frac{Observed\ Frequency}{Total}

For roll 4

Observed\ frequency = 20

So, the relative frequency is:

RF = \frac{20}{90}

Simplify

RF = \frac{2}{9}

<em>(a) is true</em>

<u>(b): Experimental probability of 3 greater than its theoretical probability</u>

The experimental probability is its relative frequency;

For roll 3

Observed\ frequency = 14

The experimental probability is:

Pr = \frac{14}{90}

Simplify

Pr = \frac{7}{45} = 0.156

To calculate  the theoretical probability, w have:

S = \{1,2,3,4,5,6\} ---- sample space

n(S)= 6

n(3) = 1 --- number of times 3 occur

The theoretical probability is:

Pr = \frac{1}{6} = 0.167

The theoretical probability is greater\ than\ the experimental probability.

<em>(b) is false</em>

<u>(c): Experimental probability of 2 greater than its theoretical probability</u>

Using the explanations in (b), we have:

For roll 2

Observed\ frequency = 16

The experimental probability is:

Pr = \frac{16}{90}

Simplify

Pr = \frac{8}{45} = 0.178

To calculate the theoretical probability, we have:

n(S)= 6

n(2) = 1

The theoretical probability is:

Pr = \frac{1}{6} = 0.167

The experimental probability is greater\ than\ the theoretical probability.

<em>(c) is true</em>

<u>(d): Relative frequency of 5 is 2/13</u>

For roll 5

Observed\ frequency = 12

The relative frequency is:

RF = \frac{12}{90}

Simplify

RF = \frac{2}{15}

<em>(d) is true</em>

7 0
2 years ago
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