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3 years ago

List 3 values that would make this inequality true. 2n ≥ 12 help

Mathematics

2 answers:

Degger [83]3 years ago

7 0

1) 6 = n
2) 9 = n
3) 11= n
This is because if we multiply anything with n it must be equal or more then 12.

Olegator [25]3 years ago

3 0

Answer:

Step-by-step explanation:

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The distance y (in centimeters) a spring is compressed by a force x (in kilograms) is given by

kirza4 [7]

Answer:

(x, y) = {(20, 1.3), (40, 2.6), (60, 3.9), (80, 5.2), (100, 6.5)}

Graph C represents the table of values

Step-by-step explanation:

To complete the table, substitute each value of x into the equation, $y = 0.065x$ , to find each corresponding y-value.

Thus:

✔️When x = 20:

$y = 0.065x$

$y = 0.065(20)$

$y = 1.3$

✔️When x = 40:

$y = 0.065x$

$y = 0.065(40)$

$y = 2.6$

✔️When x = 60:

$y = 0.065x$

$y = 0.065(60)$

$y = 3.9$

✔️When x = 80:

$y = 0.065x$

$y = 0.065(80)$

$y = 5.2$

✔️When x = 100:

$y = 0.065x$

$y = 0.065(100)$

$y = 6.5$

✔️The graph of that represents this table of values is graph C. See attachment.

6 0

4 years ago

6.1.3

Nata [24]

Answer:

The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are µ = 0 and σ = 1.

Step-by-step explanation:

A normal-distribution is an accurate symmetric-distribution of experimental data-values.

If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.

If X $\sim$ N (µ, σ²), then $Z=\frac{X-\mu}{\sigma}$ , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z $\sim$ N (0, 1).

The distribution of these z-variates is known as the standard normal distribution.

Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are µ = 0 and σ = 1.

8 0

3 years ago

What is the solution to log2(2x^3-8)-2log2(x)=log2(x)

Charra [1.4K]

$\bf \textit{Logarithm of rationals}
\\\\
log_a\left( \frac{x}{y}\right)\implies log_a(x)-log_a(y)
\\\\\\
\textit{Logarithm of exponentials}
\\\\
log_a\left( x^b \right)\implies b\cdot log_a(x)\\\\
-------------------------------$

$\bf log_2(2x^3-8)-2log_2(x)=log_2(x)
\\\\\\
log_2(2x^3-8)-log_2(x^2)=log_2(x)\implies log_2\left( \cfrac{2x^3-8}{x^2} \right)=log_2(x)
\\\\\\
\textit{since both sides are getting }log_2\textit{ we can simply undo that}
\\\\\\
\cfrac{2x^3-8}{x^2}=x\implies 2x^3-8=x^3\implies x^3-8=0
\\\\\\
x^3=8\implies x=\sqrt[3]{8}\implies x=2$

5 0

3 years ago

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Which problem solving strategy would be best to solve this problem?

Sauron [17]

Answer:

The correct option is;

B. Use a formula

Step-by-step explanation:

Given that Jim and Lillian have the dimensions of the wall they want to paint, therefore, in order to know how much paint they need to buy, they should proceed as follows;

1) Determine the quantity of paint required to paint a unit area of the wall, and record the quantity UA

2) Calculate the area, A, of the wall they want to paint, which is 15 ft. × 9 ft. = 135 ft.²

3) The amount of paint needed, AmP is therefore given by the following formula

AmP = A × AU = 135 × AU

6 0

3 years ago

A group of friends wants to go to the amusement park. They have no more than $175

vovangra [49]

Answer: 10 people can/ 12.50+16.25x is less than or equal to 175

Step-by-step explanation: so parking is constant since it doesn't change. ticket price however is affected by a variable which represents ticket per person which is shown as 12.50(parking)+16.25x where x would equal the max amount of people while respecting the given 175 limit we cannot go over

7 0

3 years ago

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