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4 years ago

6

Answer number 32 please

2 answers:

liraira [26]4 years ago

6 0

The answer is c.All rectangles are quadrillaterals and parralellograms.

son4ous [18]4 years ago

5 0

Can u help me bryson is laying down sod in his yard to grow a new lawn each piece of sod is a 1 foot by 1 foot square how many pieces of sod will bryson need to cover his yard if his yard measures 3 feet by 8 feet ?

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Simplify the expression below as much as possible (6-i)+(4+2i)-(-2+i)

Luba_88 [7]

Answer:

=6-i+4+2i+2-i

=6+4+2+2i-i-i

=12+2i-2i

=12

4 0

3 years ago

A cylinder has a base with a radius of 5 cm and a height of 15 cm. What is the volume of the cylinder? (Use π = 3.14.) A. 471 cm

eduard

The formula for volume is
$V=\pi r^{2}h$
We plug in:
$V=\pi (5)^{2}(15)$
$=\pi (25)(15)$
$=375\pi$
$=375*3.14=1177.5$

5 0

4 years ago

Read 2 more answers

The area of rectangular field is (49m2-42m+9).Find the dimensions of the field

Drupady [299]

Answer:

The dimensions are (7m-3) by (7m-3)

Step-by-step explanation:

We have the area of the rectangular field to be:

$49 {m}^{2} - 42m + 9$

We need to factorize this expression.

Let us rewrite to obtain:

${(7m)}^{2} - 2(7 \times 3)m + {3}^{2}$

We can easily see that the expression is actually a perfect square trinomial.

This gives us:

$(7m - 3)^{2}$

Or

$(7m - 3)(7m - 3)$

6 0

3 years ago

On one day a pet store sells 2 birds 6 gerbils 3 fish and 3 hamsters whats the data and relative frequency as a percent?

bonufazy [111]

Answer:

Birds $F_b=14.3\%$

Gerbils $F_g=42.9\%$

Fish $F_f=21.4\%$

Hamsters $F_h=21.4\%$

Step-by-step explanation:

From the question we are told that:

Sales

Number of birds $n_b=2$

Number of gerbils $n_g=6$

Number of fish $n_f=3$

Number of hamsters $n_h=3$

Generally the frequency for birds $F_b$ is mathematically given b

$F_b=\frac{n_b}{n}*100$

$F_b=\frac{2}{14}*100$

$F_b=14.3\%$

Generally the frequency for Gerbils $F_g$ is mathematically given b

$F_g=\frac{n_g}{n}*100$

$F_g=\frac{6}{14}*100$

$F_g=42.9\%$

Generally the frequency for fish $F_f$ is mathematically given b

$F_f=\frac{n_f}{n}*100$

$F_f=\frac{3}{14}*100$

$F_f=21.4\%$

Generally the frequency for fish $F_h$ is mathematically given b

$F_h=\frac{n_h}{n}*100$

$F_h=\frac{3}{14}*100$

$F_h=21.4\%$

5 0

3 years ago

What does 8-2(y+4)=1/2(8y-12) equal?

JulsSmile [24]

y = 1

8-2y - 8 = 4y - 6

-2y = 4y - 6

-6y = -6

y = 1

3 0

3 years ago

Read 2 more answers