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lilavasa [31]
2 years ago
11

Graph 0.6 on a vertical number line

Mathematics
1 answer:
vazorg [7]2 years ago
6 0
Next to 0. 7 on the number line
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Find the area of a parallelogram with these dimensions.
aev [14]
The area is 14! hope this helps
3 0
3 years ago
HELPPPP!!!PLEASE!!!!!
lbvjy [14]

Answer:

x=40

Step-by-step explanation:

Both angles are equal. So the equation needs to equal 156.

Just plug in points for x until the answer is 156.

In this case, when we plug in 40, it works!

(3*40)+36=156

3 0
2 years ago
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Between which two integers does square root of 76 lie?
Alecsey [184]
Answer is B, because 8*8=64 and 9*9=81. 76 lies between 64 and 81.
8 0
3 years ago
PLZ HELP I ONLY HAVE A FEW MINS LEFT
Sholpan [36]

Answer:

The area is 10 square units

Step-by-step explanation:

A = 1/2bh

A = 1/2(4)(5)

A = 10 square units

Hope this is accurate & helpful!

7 0
2 years ago
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How do I solve question 6 through 8?<br> Solve for me
rewona [7]

The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

A quadratic function is represented as:

y = a(x - h)^2 + k

<u>Question #6</u>

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

<u>Question #7</u>

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

<u>Question #8</u>

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

a = -1

Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

Read more about parabola at:

brainly.com/question/1480401

#SPJ1

5 0
1 year ago
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