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serg [7]
3 years ago
13

If y = -5x + 2 were changed to y=-7x+ 5, how would the graph of the new line compare with the first one? A. The new graph would

be less steep than the original graph, and the y-intercept would shift down 2 units. B. The new graph would be less steep than the original graph, and the y-intercept would shift up 3 units. O C. The new graph would be steeper than the original graph, and they intercept would shift down 2 units. D. The new graph would be steeper than the original graph, and the y intercept would shift up 3 units.​
Mathematics
1 answer:
Anika [276]3 years ago
5 0

D- The new graph would be steeper than the original graph, and the y- intercept would shift up 3 units.

The purple line is y=-5x + 2

The pink line is y = -7x + 5

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Lines MN and PQ are parallel. Lines RS and TV intersect them. Which statements are true about these lines? Check all that apply.
Maru [420]
<span><u><em>The correct answer is: </em></u>
RS is perpendicular to MN and PQ.

<u><em>Explanation</em></u><span><u><em>: </em></u>
We can use the slopes of these lines to determine the answer.
<u>Slope is given by the formula </u>
m=</span></span>\frac{y_{2}- y_{1}  }{ x_{2} - x_{1} }<span><span>.

<u>Using the coordinates for M and N, we have: </u>
m=</span></span>\frac{3--1}{3--3} = \frac{4}{6} = \frac{2}{3}<span><span>.

Since <u>PQ is parallel to MN</u>, its slope will be </span></span>\frac{2}{3}<span><span> as well, since parallel lines have the same slope.

<u>Using the coordinates for points T and V in the slope formula, we have </u>
m=</span></span>\frac{-4-1}{0--4} =- \frac{5}{4}<span><span>.

This is <u>not parallel to MN or PQ</u>, since the slopes are not the same.
We can also say that it <u>is not perpendicular to these lines</u>; perpendicular lines have slopes that are negative reciprocals (they are opposite signs and are flipped). This is not true of TV either.

<u>Using the coordinates for R and S in the slope formula, we have </u>
m=</span></span>\frac{-2-1}{2-0} =- \frac{3}{2}<span><span>. Comparing this to the slope of RS, it is <u>flipped and the sign is opposite</u>; they are negative reciprocals, so they are <u>perpendicular.</u></span></span>
7 0
4 years ago
Read 2 more answers
At the city museum, child admission is $5.60 and adult admission is $9.60. On Thursday, 153 tickets were sold for a total sales
JulsSmile [24]

Answer:

95 child tickets

Step-by-step explanation:

a+c =153       c=( 153-a) you need to plug this for c

9.6a + 5.6(153-a) = 1088.8

9.6a + 856.8 - 5.6a = 1088.8

4a +856.8 = 1088.8

subtract 856.8 on both sides

4a = 232

a=58   (58 adults)

153 - 58 = 95 (95 children)

95*$ 5.6 =  $532

85 *$ 9.6 =$ 556.8

$532 + $556.8 =$ 1088.8

7 0
3 years ago
examine the graph below. select the solutions to the graph from the following points. select three that apply.
vova2212 [387]

Answer:

Options (1), (2), (3)

Step-by-step explanation:

Let the equation of the line is,

y = mx + b

Here m = slope of the line

b = y-intercept

Given line on the graph is passing through two points (-3, 0) and (0, 1).

Slope of this line will be,

m = \frac{y_2-y_1}{x_2-x_1}

   = \frac{1-0}{0+3}

   = \frac{1}{3}

y-intercept of the line 'b' = 1

Equation of the line will be,

y = \frac{1}{3}x+1

If the points given in the options satisfy the equation, they will be the solution of the line.

Option (1),

For (3, 2),

2 = \frac{3}{3}+1

2 = 2

True.

(3, 2) is the solution.

Option (2)

For (21, 8),

8 = \frac{21}{3}+1

8 = 8

True.

(21, 8) is the solution.

Option(3)

For (-15, -4),

-4 = \frac{-15}{3}+1

-4 = -4

True.

(-15, -4) is the solution.

Option (4)

For (12, 9)

9 = \frac{12}{3}+1

9 = 5

False

(12, 9) is not the solution.

Option (5)

For (-6, 1)

1 = \frac{-6}{3}+1

1 = -1

False

(-6, 1) is not the solution.

Therefore, Options (1), (2), (3) are the solutions.

5 0
3 years ago
The expression (4z + 3)(z - 2) is equivalent to
harkovskaia [24]

(4z + 3)(z - 2)=4z^2-8z+3z-6=4z^2-5z-6

8 0
4 years ago
Find the distance between (1, 2) and (-3, -2)
loris [4]
Answer: fjfkmfbdi

Explain irithriejeieogkde
4 0
3 years ago
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