Write an equation in slope intercep form that passes thru the points (10,2) and (2,-2)

Rewrite the expression with a rational exponent as a radical expression.

Vilka [71]

Answer:

$\sqrt{5}$

Step-by-step explanation:

we know that

The "power rule" tells us that to raise a power to a power, just multiply the exponents

so

$(a^{m})^{n}=a^{m*n}$

we have

$(5^{\frac{3}{4}})^{\frac{2}{3}}$

Applying the "power rule"

$(5^{\frac{3}{4}})^{\frac{2}{3}}=5^{\frac{3}{4}*\frac{2}{3}}=5^{\frac{1}{2}}=\sqrt{5}$

5 0

3 years ago

Y=-(5)^2=-100 how do I do that

Leona [35]

All you have to use is pemdas and keep y by itself

7 0

3 years ago

Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)If the coin is flipped 3 times, what is

Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since, its head is twice as likely to occur as its tail.

$p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}$

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n = 3

$p=\dfrac{2}{3}$

$q=\dfrac{1}{3}$

Now,

$P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222$

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

$P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292$

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

$P(X\leq 1)=\sum _{x=0}^1^4C_x(\dfrac{2}{3}^x(\dfrac{1}{3})^{4-x}=0.1111$

Hence, a) 0.2222, b) 0.3292, c) 0.1111

8 0

3 years ago

Can someone please help mee

Andrew [12]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:Domain = [-9, -1]$

$\qquad \tt \rightarrow \:Range = [-1 , 3]$

____________________________________

$\large \tt Solution \: :$

Domain = All possible values of x for which f(x) is defined

[ generally the extension of function in x - direction ]

Range = All possible values of f(x)

[ generally the extension of function in y - direction ]

$\large\textsf{For the given graph : }$

$\qquad \tt \rightarrow \: domain = [ - 9, -1]$

$\qquad \tt \rightarrow \: range= [ -1,3]$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

3 0

2 years ago

PLEASE HELP ASAP!!!!

Setler [38]

Piecewise Function is like multiple functions with a speific/given domain in one set, or three in one for easier understanding, perhaps.

To evaluate the function, we have to check which value to evalue and which domain is fit or perfect for the three functions.

Since we want to evaluate x = -8 and x = 4. That means x^2 cannot be used because the given domain is less than -8 and 4. For the cube root of x, the domain is given from -8 to 1. That meand we can substitute x = -8 in the cube root function because the cube root contains -8 in domain but can't substitute x = 4 in since it doesn't contain 4 in domain.

Last is the constant function where x ≥ 1. We can substitute x = 4 because it is contained in domain.

Therefore:

$\large{ \begin{cases} f( - 8 ) = \sqrt[3]{ - 8} \\ f(4) = 3 \end{cases}}$

The nth root of a can contain negative number only if n is an odd number.

$\large{ \begin{cases} f( - 8 ) = \sqrt[3]{ - 2 \times - 2 \times - 2} \\ f(4) = 3 \end{cases}} \\ \large{ \begin{cases} f( - 8 ) = - 2\\ f(4) = 3 \end{cases}}$

Answer

f(-8) = -2
f(4) = 3

6 0

2 years ago