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Lubov Fominskaja [6]
4 years ago
15

Find m+n.

Mathematics
1 answer:
Alik [6]4 years ago
6 0
Easy Peasy Lemon Squeezy.

it's difficult because you are looking too hard. think simply. why does it tell you that angle is 40°?

Because if you follow the arrow back to where it starts you will see that exact same angle.

so now you know 1 (not m° or n°) angle inside the triangle is 40° and a complete triangle is 180°.

you also know a straight line has 180° on each side. and the line going from m° to n° splits that in half. meaning there is 90° to the right of it and 90° to the left of it. which means n° must equal 90°.

now you know you have 1 angle inside the triangle with 40° and n°=90° now you just need to find how much m° is.

add 40°+90° then Subtract from 180° to get m°.

180°-130°=50°
m°=50°
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Answer:

a) Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}  

b) z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{688+671}{989+1012}=0.679  

c) z=\frac{0.696-0.663}{\sqrt{0.679(1-0.679)(\frac{1}{989}+\frac{1}{1012})}}=1.58    

d) For this case we see that \hat p_1 > \hat p_2 so then the answer for this cae would men

Step-by-step explanation:

Information given

X_{1}=688 represent the number of men with smartphone  

X_{2}=671 represent the number of women with smartphone

n_{1}=989 sample of men selected

n_{2}=1012 sample of women selected

p_{1}=\frac{688}{989}=0.696 represent the proportion of men with smartphone

p_{2}=\frac{671}{1012}=0.663 represent the proportion of women with smartphone

\hat p represent the pooled estimate of p

z would represent the statistic

p_v represent the value

Part a

We want to test if we have difference in the proportion owning a smartphone between men and women, the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

Part b

The statistic for this case is given by:

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{688+671}{989+1012}=0.679  

Part c

Replacing the info given we got:

z=\frac{0.696-0.663}{\sqrt{0.679(1-0.679)(\frac{1}{989}+\frac{1}{1012})}}=1.58    

Part d

For this case we see that \hat p_1 > \hat p_2 so then the answer for this cae would men

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