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2 years ago

What percent's falls between 0.5 and 0.6

1 answer:

6 0

5 rational numbers between 0.5 and 0.6 can be any 5 numbers up to any number of decimal places that lies between 0.5 and 0.6. Or, it can also be 0.5124, 0.5676, 0.588, 0.59, 0.5789.S

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What is the quotient?

ryzh [129]

Answer:

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Step-by-step explanation:

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3 years ago

Divide the following polynomials, then place the answer in the proper location on the grid. Write answer in descending powers of

irina1246 [14]

Let's rewrite the expression correctly:
(12x3 - 11x2 + 22x - 5) / (4x -1)
Dividing the expression between (4x -1) we have:
3x2 - 2x + 5
We can check the result:
(3x2 - 2x + 5) * (4x-1)
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Division OK.
Answer:
The result of the division is:
3x2 - 2x + 5

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3 years ago

find the coordinates of the vertex of the following parabola algebraically. write your answer as an (x, y) point. y = -3x^2 + 48

77julia77 [94]

Answer:(8,-3)

Step-by-step explanation:

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3 years ago

Could Keenan have started with 6 strawberries? Use your expression to explain why or why not.

Dahasolnce [82]

Note: you may have unintentionally missed to add the complete question. Therefore, after a little research, I am able to find the complete question which I am attaching to solve your query, which anyways would clear your concept.

The complete Question:

Keenan gives Tisha half of his strawberries. Tisha keeps 4 of the strawberries she got from Keenan and gives the rest to Suvi.

a) Write an expression for the number of strawberries Tisha gives to Suvi. Use k for the number of strawberries Keenan started with.

b) Could Keenan have started with 6 strawberries? Use your expression to explain why or why not.

Answer:

Part a)

An expression for the number of strawberries Tisha gives to Suvi will be: $n=\frac{k}{2} -4$

Part b)

Keenan could not have started with 6 strawberries

Step-by-step explanation:

Part a) Write an expression for the number of strawberries Tisha gives to Suvi. Use k for the number of strawberries Keenan started with.

Let $k$ be the total number of strawberries which Keenan has.

So,

$\frac{k}{2}$ is the number of strawberries Keenan gave to Tisha.

As Tisha keeps 4 strawberries and gives the rest to Suvi. Let $n$ be the number of strawberries which Suvi has.

So,

$n=\frac{k}{2} -4$

$\frac{k}{2}=n+4$

$k=2n+8$

Therefore, an expression for the number of strawberries Tisha gives to Suvi will be: $n=\frac{k}{2} -4$

b) Could Keenan have started with 6 strawberries? Use your expression to explain why or why not.

Considering the expression for the number of strawberries Tisha gives to Suvi

$n=\frac{k}{2} -4$

Putting $k = 6$ in the expression

$n=\frac{6}{2} -4$

Solving the expression

$n=3-4$ ∵ $\mathrm{Divide\:the\:numbers:}\:\frac{6}{2}=3$

$\mathrm{Subtract\:the\:numbers:}\:3-4=-1$

$n=-1$

So, Keenan would have started with 6 strawberries, then Suvi would have -1 strawberries. Since, strawberries cannot be negative as Suvi cannot have negative number of strawberries.

Therefore, Keenan could not have started with 6 strawberries.

Keywords: word problem, expression

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3 years ago