Question

The weight needed to balance a lever varies inversely with the distance

Answer 1

Let w represents the weight and d represents the distance.

It is given that

The weight needed to balance a lever varies inversely with the distance from the fulcrum to the weight. A 120-lb weight is placed on a lever, 5 ft from the fulcrum.

$w = \frac{k}{d}$

Substituting the values of w and d, we will get

$120= \frac{k}{5} \\ k =600lb \ ft$

Using the value of k which is 600, with the above equation and the given value of d which is 8, we will get

$w = \frac{600}{8} = 75lb$

Therefore the correct option is B .