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Alik [6]
3 years ago
10

A ball is thrown from an initial height of 2 meters with an initial upward velocity of 15/ms . The ball's height h (in meters) a

fter t seconds is given by the following. =h+2−15t5t2 Find all values of t for which the ball's height is 7 meters. Round your answer(s) to the nearest hundredth. (If there is more than one answer, use the "or" button.)

Mathematics
1 answer:
Irina-Kira [14]3 years ago
4 0
The height that a ball reaches at a certain time t is given by the equation,
           h = 2 - 15t + 5t²
We are asked to compute for the values of t that would allow the ball to reach a height of 7 meters. 

Substitute the 7 to the equation,
         7 = 2 - 15t + 5t²
Transposing,
               5t² - 15t - 7 + 2 = 0
Simplifying,
               5t² - 15t - 5 = 0
Divide the equation by 5,
               t² - 3t - 1 = 0

The values of t can be calculated through the quadratic formula,
             t = (-b +/- sqrt(b² - 4ac))/2a

Substituting, 
             t = (3 +/-sqrt (9 - 4(-1)) / 2(1)
              t = 3.3 or t = -0.30

Since, we cannot have t as a negative number hence, our final answer is:
      <em> t = 3.3 s</em>
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What is the value of x to the nearest<br> tenth?
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Answer:

C. 17.6

General Formulas and Concepts:

<u>Math</u>

  • Rounding

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Trigonometry</u>

  • [Right Triangles Only] SOHCAHTOA
  • [Right Triangles Only] tanθ = opposite over adjacent

Step-by-step explanation:

<u>Step 1: Identify Variables</u>

Angle θ = 40°

Opposite Leg = <em>x</em>

Adjacent Leg = 21

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute in variables [tangent]:                                                                   \displaystyle tan(40^\circ) = \frac{x}{21}
  2. [Multiplication Property of Equality] Isolate <em>x</em>:                                                \displaystyle 21tan(40^\circ) = x
  3. Rewrite:                                                                                                           \displaystyle x = 21tan(40^\circ)
  4. Evaluate:                                                                                                          \displaystyle x = 17.6211
  5. Round:                                                                                                            \displaystyle x \approx 17.6
6 0
2 years ago
Read 2 more answers
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