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Vsevolod [243]
3 years ago
14

A 11-inch candle is lit and burns at a constant rate of 1.3 inches per hour. Let t represent the number of hours since the candl

e was lit, and suppose f is a function such that f ( t ) represents the remaining length of the candle (in inches) t hours after it was lit. Write a function formula for f .
Mathematics
1 answer:
dem82 [27]3 years ago
8 0

Answer:

f(t)= 11 in - 1.3 in/h *t

Step-by-step explanation:

defining the length of the candle as L , then since the candle burns at a constant rate , then

-dL/dt = 1.3 in/h = a

therefore

-∫dL = a∫dt

-L(t)=a*t + C , C=constant

at t=0 , the length of the candle is L₀= 11 in ,thus

-L₀=a*0 + C →  C= -L₀

replacing the value of C

-L(t)=a*t - L₀

L(t) = L₀ - a*t = 11 in - 1.3 in/h *t

then

f(t)= 11 in - 1.3 in/h *t

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lozanna [386]
Hi there!

Let's solve this equation step by step!
6f + 9g = 3g + f

To solve for f, we need to bring all the terms in the equation with an f in it to the left, and all the other terms (with a g) to the right.

First subtract f from both sides.
5f + 9g = 3g

Now subtract 9g from both sides.
5f = -6g

And finally divide both sides by 5.
f = (-6/5)g

Hence, your answer;
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~ Hope this helps you!
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What second degree polynomial function has a leading coefficient of -2 and root 4 with a multiplicity of 2
OverLord2011 [107]

The second degree polynomial with leading coefficient of -2 and root 4 with multiplicity of 2 is:

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<h3>How to write the polynomial?</h3>

A polynomial of degree N, with the N roots {x₁, ..., xₙ} and a leading coefficient a is written as:

p(x) = a*(x - x_1)*(x - x_2)*...*(x - x_n)

Here we know that the degree is 2, the only root is 4 (with a multiplicity of 2, this is equivalent to say that we have two roots at x = 4) and a leading coefficient equal to -2.

Then this polynomial is equal to:

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Answer:

6) Two angles are called supplementary when their measures add up to 180 degrees. For example, two right angles are supplementary angles.

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Step-by-step explanation:

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