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Luden [163]
2 years ago
12

Please help quickly. 1 the circumference (c) of a circle is not less than 77 cm find the range of the values of the radius take

pi to be 22/7 2. a woman is 14 years older than her son. In five years time,the son will not be more than 36 years old what is the likely range of the present age of the present age of the Son 3 . a rectangle is 10 cm long and x cm broad find the range of x cm if the perimeter of the rectangle is not greater than 60 cm and not less than 20 cm 4.Given that q is a whole number if one quarter of a is subtracted from 1 the result is always greater than 3 find the two highest values of q....
NOTE: IF YOU ARE NOT SURE OF EVERYTHING PLEASE ANSWER THE ONE YOU KNOW,AND EXPECT A BRAINLIEST!THANK YOU SO MUCH:)​
Mathematics
1 answer:
34kurt2 years ago
5 0

Answer:

importance of development

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Answer:

0.60 - 1.96\sqrt{\frac{0.60(1-0.60)}{1019}}=0.570

0.60 + 1.96\sqrt{\frac{0.60(1-0.60)}{1019}}=0.630

The 95% confidence interval for the true proportion would be given by (0.570;0.630) .

And if we convert this into % we got (57.0%, 63.0%)

Step-by-step explanation:

The information given we have the following info given:

n = 1019 represent the sampel size

\hat p=0.6 represent the sample proportion of interest

The confidence level is 95%, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

Replacing the info given we got:

0.60 - 1.96\sqrt{\frac{0.60(1-0.60)}{1019}}=0.570

0.60 + 1.96\sqrt{\frac{0.60(1-0.60)}{1019}}=0.630

The 95% confidence interval for the true proportion would be given by (0.570;0.630) .

And if we convert this into % we got (57.0%, 63.0%)

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Answer:

it is the second choice

Step-by-step explanation:

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\left[\begin{array}{cc}Juice&Water\\1&3\\2&6\\3&9\\4&12\\\end{array}\right]

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See the picture

Step-by-step explanation:

The answer is attached

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