Answer: ok so Let's simplify step-by-step.
r−3q+5p−(−4r−3q−8p)
Distribute the Negative Sign:
=r−3q+5p+−1(−4r−3q−8p)
=r+−3q+5p+−1(−4r)+−1(−3q)+−1(−8p)
=r+−3q+5p+4r+3q+8p
Combine Like Terms:
=r+−3q+5p+4r+3q+8p
=(5p+8p)+(−3q+3q)+(r+4r)
=13p+5r
Step-by-step explanation:
Answer:
The answer is C.
Step-by-step explanation:
Given formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height.
In this case, the initial postion is a platform 30ft above ground so h0=+30
The initial velocity is 38 ft/s straight up into the air so v0=+38
h(t)=-16t2+38t+30
When the object hits the ground, h=0.
h=-16t2+38t+30=0
Simplifying 8t2-19t-15=0
(8t+5)(t-3)=0
t=-5/8 or 3
As time cannot be -ve, t=3s. The answer is C.
Answer:
It will be equal to 40
Step-by-step explanation:
We have to compute 
Let first find 3 !
For this we have to use factorial concept
So 3! will be equal to 3! = 3×2×1 = 6
Now According to 6+2 = 8
And now after solving bracket we have to multiply with 5
So 5×8 = 40
So after computation 
So the final answer will be 40
Answer:
5
Step-by-step explanation:
we take the 5 behind the four and it rounds up to a 5
4.5=5
