Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
Assume a normal distribution :
Mean (m) = 328
Standard deviation (sd) = 92
To obtain Zscore :
Zscore = (x - m) / sd
What is the probability that the cost will be more than $500?
x = $500
Zscore = (500 - 328) / 92 = 172 / 92 = 1.869 = 1.87
1 - p(Z < 1.87) = 1 - 0.9693 = 0.0307
b. What is the probability that the cost will be less than $250?
x = $250
Zscore = (250 - 328) / 92 = - 78 / 92 = - 0.8478 = - 0.85
p(Z < - 0.85) = 0.1977
c. What is the probability that the cost will be between $300 and $400?
x = 300
Zscore = (300 - 328) / 92 = - 28/ 92 = -0.30
p(Z < - 0.3) = 0.3821
x = 400
Zscore = (400 - 328) / 92 = 72/ 92 = 0.783
p(Z < 0.783) = 0.7823
0.7823 - 0.3821 = 0.4002
d. If the cost to a patient is in the lower 8% of charges for this medical service, what was the cost of this patient’s emergency room visit?
Probability is lower 8%
P (Z < Zscore) = 0.08
Zscore of 0.08 corresponds to - 1.41 on the z table
Zscore = (x - m) / sd
-1.41 = (x - 328) / 92
-129.72 = x - 328
-129.72 + 328 = x
x = 198.28
We are given with the expression <span>tan2x / x</span> and asked to evaluate the expression to limit as theta approaches zero. In this case, we substitute first zero. The answer is zero over zero. This is indeterminate so we derive the terms accdg to L'hopital's rule. The derivative is 2 sec^2 2x/1. cos 2x is 1 so is sec^2 2x. Hence the answer is 2.
Answer:
It can be modeled with the equation
but needs a starting population number to finish.
Step-by-step explanation:
To find the population in a future year, use the formula:

where A is the amount, p is the starting population, r is 2% or 0.02, and t is the number of years.
Since the population is increasing it is addition. Substitute r=0.02 and t=6. Without a starting population, we cannot find the population in 6 years.

87 + 34
87 rounded = 90
34 rounded = 35
90 + 35 = 125
or
87 rounded = 90
34 rounded = 30
90 + 30 = 120
when rounding you are only getting an estimate so it is not going to be exact however you do it.