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sattari [20]
2 years ago
13

Sandra throws an object straight up into the air with an initial velocity of 38 ft/s from a platform that is 30 ft above the gro

und. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?
A. 1 s

B. 2 s

C. 3 s

D. 4 s
Mathematics
2 answers:
Makovka662 [10]2 years ago
6 0

Answer:

The answer is C.

Step-by-step explanation:

Given formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height.

In this case, the initial postion is a platform 30ft above ground so h0=+30

The initial velocity is 38 ft/s straight up into the air so v0=+38

h(t)=-16t2+38t+30

When the object hits the ground, h=0.

h=-16t2+38t+30=0

Simplifying 8t2-19t-15=0

(8t+5)(t-3)=0

t=-5/8 or 3

As time cannot be -ve, t=3s. The answer is C.

Vikentia [17]2 years ago
4 0

Answer:

C

Step-by-step explanation:

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2 years ago
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Evaluate the expression(-3.8)+0+y for the given values of y.
11111nata11111 [884]

Answer:

y = -3.3 then  -7.1

y = -7.1 then  -10.9

y = -2.6 then -6.4

y = 1 then -2.8

y = 4.2 then 0.4

Step-by-step explanation:

(-3.8)+0+y can be simplified to -3.8 + y. Evaluate each value for y by substituting it into the expression and solving.

y = -3.3 then -3.8 + -3.3 = -7.1

y = -7.1 then -3.8 + -7.1 = -10.9

y = -2.6 then -3.8 + -2.6 = -6.4

y = 1 then -3.8 + 1 = -2.8

y = 4.2 then -3.8 + 4.2 = 0.4

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3 years ago
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8y=2x is the same as y=0.25x. It is direct variation, and the constant is 0.25

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3 years ago
In a sample of eight whitefish caught in Yellowknife Bay, the mean arsenic concentration in the liver was 0.32 mg/kg, with a sta
Advocard [28]

Answer:

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 7

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 7 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.3246

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.3646\frac{0.06}{\sqrt{8}} = 0.0502

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.32 - 0.0502 = 0.2698 mg/kg

The upper end of the interval is the sample mean added to M. So it is 0.32 + 0.0502 = 0.3702 mg/kg

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

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