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3 years ago

10

What is the largest number of three consecutive integers whose sum is 42? O A. 13 B. 17 O C. 15 D. 12

1 answer:

wolverine [178]3 years ago

5 0

Answer: 13

Step-by-step explanation:

3X + 3 - 3 = 42 - 3

3X = 39

3X/3 = 39/3

X = 13

Which means that the first number is 13, the second number is 13 + 1 and the third number is 13 + 2. Therefore, three consecutive integers that add up to 42 are 13, 14, and 15.

13 + 14 + 15 = 42

We know our answer is correct because 13 + 14 + 15 equals 42 as displayed above.

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