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kifflom [539]
3 years ago
10

What is the largest number of three consecutive integers whose sum is 42? O A. 13 B. 17 O C. 15 D. 12​

Mathematics
1 answer:
wolverine [178]3 years ago
5 0

Answer: 13

Step-by-step explanation:

3X + 3 - 3 = 42 - 3

3X = 39

3X/3 = 39/3

X = 13

Which means that the first number is 13, the second number is 13 + 1 and the third number is 13 + 2. Therefore, three consecutive integers that add up to 42 are 13, 14, and 15.

13 + 14 + 15 = 42

We know our answer is correct because 13 + 14 + 15 equals 42 as displayed above.

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allochka39001 [22]

676 + 100 = 776

676 + 101 = 777

676 + 102 = 778

676 + 103 = 779

6 0
2 years ago
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Without calculating, would 0.4+(2+0.6) be less than , greater than, or equal to 3? Explain.
Ainat [17]
It would be greater than three because it is addition and when you add it is to increase not decrease. good luck!
6 0
3 years ago
A rectangular prism has a length of 4 cm a width of 6 cm and a height of 3 cm what is it’s volume
liraira [26]

Answer: 72

Step-by-step explanation:

8 0
3 years ago
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Max was on vacation twice as long is Jared and half as long as Wesley. The boys were on vacation a total of three weeks. How man
nasty-shy [4]
To begin with, the question is asking for the answer in days, so let's change 3 weeks to days. There are 7 days in 1 week; 3 weeks times 7 days = 21 days.
21 total days of vacation.

Max + Jared + Wesley = 21 days
(Let's use the first letter of their name to represent their vacation time)

M + J + W = 21 [This is the equation we'll be coming back to]

Now, we can use the clues given in the question to have an equation for each variable/boy. 

Max was on vacation twice as long as Jared. We can interpret this as  M= 2J Max was on vacation only half as long as Wesley. We can interpret this as M = (1/2)W.

So far we have these three equations: M + J + W = 21M = 2J M = (1/2)W

To have an equation for each individual boy, we must rearrange the last two equations in the list.

First, M = 2J.
Divide both sides by 2
M/2 = 2J/2
(1/2)M = J

Second, <span>M = (1/2)W
Multiply both sides by 2
2M = W

New equations:
</span><span>M + J + W = 21 [From the old list]
</span>J = (1/2)W
W = 2M

Now we can substitute the last two equations into the first one. 
M + J + W = 21
M + (1/2)W + 2M = 21
[Combine Like Terms]
<span>(7/2)M = 21 
</span>
Then, solve for M (Max's vacation days):
Multiply both sides by 2/7
(\frac{2}{7})* (\frac{7}{2}m)= (\frac{2}{7})*(21)
M = 6

Now we know Max was on vacation for 6 days.

If Max was on vacation twice as long as Jared, that means Jared was on vacation HALF as long as Max.

So...
<span>J = (1/2)M 
J = (1/2) * 6
J = 3
Jared was on vacation for 3 days 
</span>
Wesley was on vacation twice as long as Max so...  W = 2M 
W= 2*6
W = 12
Wesley was on vacation for 12 days. 

Let's double check our answer:
M + J + W = 21 days<span>6 + 3 + 12 = 21   
The numbers work out so the math is correct. Hope this helps and makes sense!</span>
6 0
3 years ago
Evaluate 5y+x2÷2 when x=4 and y=−3. When x=4 and y=−3, 5y+x2÷2=
Alex Ar [27]
The answer is 5 x -3 + 4 x 2 / 2 = -15 + 8 / 2 = -11
6 0
3 years ago
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