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kifflom [539]
3 years ago
10

What is the largest number of three consecutive integers whose sum is 42? O A. 13 B. 17 O C. 15 D. 12​

Mathematics
1 answer:
wolverine [178]3 years ago
5 0

Answer: 13

Step-by-step explanation:

3X + 3 - 3 = 42 - 3

3X = 39

3X/3 = 39/3

X = 13

Which means that the first number is 13, the second number is 13 + 1 and the third number is 13 + 2. Therefore, three consecutive integers that add up to 42 are 13, 14, and 15.

13 + 14 + 15 = 42

We know our answer is correct because 13 + 14 + 15 equals 42 as displayed above.

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Answer:

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Step-by-step explanation:

Given

6x² - 14x - 12 ← factor out 2 from each term

= 2(3x² - 7x - 6) ← factor the quadratic

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 3 × - 6 = - 18 and sum = - 7

The factors are - 9 and + 2

Use these factors to split the x- term

3x² - 9x + 2x - 6 ( factor the first/second and third/fourth terms )

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Thus

3x² - 7x - 6 = (x - 3)(3x + 2) and

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